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anonymous

  • 5 years ago

what is the number of solutions to the system? x + y = -1 5x - 5y = 7

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  1. anonymous
    • 5 years ago
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    someone please help me! i dont get this

  2. M
    • 5 years ago
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    solve for x then plug it in the second equation

  3. anonymous
    • 5 years ago
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    so i would set it up like x + y = -1 = 5x - 5y = 7 ?

  4. M
    • 5 years ago
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    x = -1 - y 5(-1 - y) -5y = 7 then you'll know what y is

  5. M
    • 5 years ago
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    if you know y then you can plug in y to first equation and find out what x is

  6. anonymous
    • 5 years ago
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    wait let me write this down and try to do that

  7. M
    • 5 years ago
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    -5 - 5y -5y = 7 -10y = 14 y = -14/10

  8. M
    • 5 years ago
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    when you have two unknown (here x and y) then you always want to solve for x or y, then plug it into the other equation so you're working with just one unknown variable

  9. anonymous
    • 5 years ago
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    ok i get the -10 y part. buy what about the -5 and where did 14 come from?

  10. anonymous
    • 5 years ago
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    ahhh. isee.

  11. M
    • 5 years ago
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    you try to get y on left and everything else on right

  12. anonymous
    • 5 years ago
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    yeah but you left -5 out. what did you do with it? and where did 14 come from?

  13. M
    • 5 years ago
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    you move -5 to right side of = sign

  14. M
    • 5 years ago
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    you want to get rid of -5 on left side so you add +5 to both side

  15. M
    • 5 years ago
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    so -5 disappears on left and +5 appears on right

  16. anonymous
    • 5 years ago
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    Okay. but that equals 12.

  17. M
    • 5 years ago
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    whatever you do on left you MUST do same on right to keep equation same

  18. M
    • 5 years ago
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    sorry it's 12 :)

  19. M
    • 5 years ago
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    12/10

  20. anonymous
    • 5 years ago
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    i know that. ahh seee. thaats why i was like huh? lol

  21. anonymous
    • 5 years ago
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    u got me confused rii there. its cool tho

  22. M
    • 5 years ago
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    so plug in y= -12/10 to find x

  23. anonymous
    • 5 years ago
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    isnt it 12/-10 ?

  24. M
    • 5 years ago
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    it doesn't matter if it's on top or bottom

  25. M
    • 5 years ago
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    it's (-1) (12/10)

  26. M
    • 5 years ago
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    ^^ that's the correct form

  27. anonymous
    • 5 years ago
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    ahhhhh i seee. so the answer is one solution.

  28. M
    • 5 years ago
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    there's only one solution for y and one for x

  29. M
    • 5 years ago
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    answer is a fraction

  30. anonymous
    • 5 years ago
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    i know. but its asking me how many solutions. one two or no solutions

  31. anonymous
    • 5 years ago
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    i have this other one. i have to find the ordered pairs. let me see if i can do it. -3x + 5y = 4 5x +5y = 60

  32. M
    • 5 years ago
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    i'm not sure what the question is asking?

  33. M
    • 5 years ago
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    there can be infinite combination of x and y and it'll give you those answers

  34. anonymous
    • 5 years ago
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    it says give the ordered pairs that satisfies the system of equations

  35. anonymous
    • 5 years ago
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    well for the other one that your talking about.... it was asking WHAT IS THE NUMBER OF SOLUTIONS TO THE SYSTEM? and i put ONE SOLUTION

  36. anonymous
    • 5 years ago
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    theres another choice that says INFINITELY MANY SOLUTIONS

  37. M
    • 5 years ago
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    i think it may be asking for just x and y like (x, y)

  38. M
    • 5 years ago
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    so just one solution

  39. anonymous
    • 5 years ago
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    yeah it is.

  40. anonymous
    • 5 years ago
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    Okay. thanks.

  41. anonymous
    • 5 years ago
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    let me see if i can do the other one.

  42. anonymous
    • 5 years ago
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    i have a question

  43. anonymous
    • 5 years ago
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    i did 5x ( -3x + 5y ) +5y = 60

  44. M
    • 5 years ago
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    no you have to solve for y first

  45. M
    • 5 years ago
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    y = (1/5)(3x +4)

  46. M
    • 5 years ago
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    then you plug it in like you did

  47. anonymous
    • 5 years ago
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    so thats how im suppose set it up rii?

  48. M
    • 5 years ago
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    i'm not sure what you did

  49. M
    • 5 years ago
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    you first either solve for x or y

  50. M
    • 5 years ago
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    then plug in the result to the second equation

  51. anonymous
    • 5 years ago
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    i want to solve for X

  52. anonymous
    • 5 years ago
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    so how do i set it up?

  53. M
    • 5 years ago
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    x = (5y - 4)(1/3)

  54. M
    • 5 years ago
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    5[(5y - 4)(1/3)] +5y = 60 the bracket [ ] is the x

  55. M
    • 5 years ago
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    now you only have one variable y in your equation since we plugged in for x

  56. anonymous
    • 5 years ago
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    where did one third come from?

  57. anonymous
    • 5 years ago
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    wait let me get this straightt....

  58. M
    • 5 years ago
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    i just plugged in for x

  59. anonymous
    • 5 years ago
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    ahh okay

  60. anonymous
    • 5 years ago
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    so now that we have our equation we have to distribute the 5 to the perenthesis (5y-4) correct?

  61. M
    • 5 years ago
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    you can do that then divide everything by 3

  62. anonymous
    • 5 years ago
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    i can distribute 5 to 1/3 righT?

  63. anonymous
    • 5 years ago
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    i can distribute 5 to 1/3 righT?

  64. anonymous
    • 5 years ago
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    i can distribute 5 to 1/3 righT?

  65. anonymous
    • 5 years ago
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    i can distribute 5 to 1/3 righT?

  66. anonymous
    • 5 years ago
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    i can distribute 5 to 1/3 righT?

  67. anonymous
    • 5 years ago
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    i can distribute 5 to 1/3 righT?

  68. anonymous
    • 5 years ago
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    i can distribute 5 to 1/3 righT?

  69. anonymous
    • 5 years ago
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    i can distribute 5 to 1/3 righT?

  70. anonymous
    • 5 years ago
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    i can distribute 5 to 1/3 righT?

  71. M
    • 5 years ago
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    you're not distributing since (1/3) is its own. you simply multiply

  72. anonymous
    • 5 years ago
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    srry about that

  73. anonymous
    • 5 years ago
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    so what i shud have is [ (25y-20) (1/3) ]

  74. anonymous
    • 5 years ago
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    [ (25y-20) (1/3) ] + 5y = 60

  75. M
    • 5 years ago
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    yeah then solve for y

  76. M
    • 5 years ago
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    now you have to distribute (1/3)

  77. anonymous
    • 5 years ago
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    im a little confused. so right this is what i have...... [ (25y-20) (1/3) ] + 5y = 60 -5y - 5y [ (20y- 20) (1/3) ] = 60

  78. M
    • 5 years ago
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    no

  79. M
    • 5 years ago
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    you don't want to move 5y to other side because you still have 25y

  80. M
    • 5 years ago
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    you want to move 20(1/3) to right

  81. M
    • 5 years ago
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    then combine 25y(1/3) + 5y

  82. M
    • 5 years ago
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    you may want to use calculator

  83. anonymous
    • 5 years ago
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    so multiply -20/2 times 1/3

  84. M
    • 5 years ago
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    remember we're trying to solve for y

  85. anonymous
    • 5 years ago
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    wait ignore that.. typo

  86. anonymous
    • 5 years ago
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    so multiply 20/1 times 1/3 then combien 25y times 1/3 + 5y then combine like terms so you'd end up with 30y (1/3)

  87. M
    • 5 years ago
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    no

  88. M
    • 5 years ago
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    you first distribute (1/3) to 25y and -20

  89. M
    • 5 years ago
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    so it's 25y(1/3) + 5y = 60 + 20(1/3)

  90. M
    • 5 years ago
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    y(25(1/3) + 5) = 60 + 20(1/3) y = 60 + 20(1/3) / (25(1/3) + 5)

  91. M
    • 5 years ago
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    it looks real messy b/c i didn't simplify anything

  92. M
    • 5 years ago
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    \[y = 60 + 20(1/3)\div (25(1/3) + 5)\]

  93. anonymous
    • 5 years ago
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    so now im gunna distribute 20 (1/3) and 25 (1/3)

  94. M
    • 5 years ago
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    no you just multiply

  95. M
    • 5 years ago
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    it's just 20/3 and 25/3

  96. M
    • 5 years ago
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    you can multiply by (1/3) or just divide by 3

  97. anonymous
    • 5 years ago
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    500\3

  98. M
    • 5 years ago
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    where'd that come from

  99. anonymous
    • 5 years ago
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    wowww. what a retardd.

  100. anonymous
    • 5 years ago
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    sorry im a little bit slow and dumb

  101. anonymous
    • 5 years ago
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    math is rlly not my thing.

  102. M
    • 5 years ago
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    \[200/3 \div 40/3\]

  103. M
    • 5 years ago
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    so it's 200/3

  104. M
    • 5 years ago
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    i mean 200/40

  105. M
    • 5 years ago
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    = 5

  106. anonymous
    • 5 years ago
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    y = 5

  107. M
    • 5 years ago
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    yeah

  108. anonymous
    • 5 years ago
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    x=7

  109. M
    • 5 years ago
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    yeah

  110. anonymous
    • 5 years ago
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    Omgg. thank you so much! you have no idea how much you've helped me!

  111. M
    • 5 years ago
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    np just remember to isolate x or y, whichever is easier. then plug that into the other equation

  112. anonymous
    • 5 years ago
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    thank youu! but the bad thing is, that on my worksheet, theres different types of problems. they never stick to one thing.

  113. M
    • 5 years ago
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    yeah, all you can do is practice. good luck

  114. anonymous
    • 5 years ago
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    yeah. thank youu! im sure ill do good on my state exam! thanks alot!

  115. M
    • 5 years ago
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    bye :)

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