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anonymous
 5 years ago
what is the number of solutions to the system?
x + y = 1
5x  5y = 7
anonymous
 5 years ago
what is the number of solutions to the system? x + y = 1 5x  5y = 7

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0someone please help me! i dont get this

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0solve for x then plug it in the second equation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so i would set it up like x + y = 1 = 5x  5y = 7 ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x = 1  y 5(1  y) 5y = 7 then you'll know what y is

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if you know y then you can plug in y to first equation and find out what x is

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait let me write this down and try to do that

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.05  5y 5y = 7 10y = 14 y = 14/10

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0when you have two unknown (here x and y) then you always want to solve for x or y, then plug it into the other equation so you're working with just one unknown variable

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok i get the 10 y part. buy what about the 5 and where did 14 come from?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you try to get y on left and everything else on right

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah but you left 5 out. what did you do with it? and where did 14 come from?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you move 5 to right side of = sign

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you want to get rid of 5 on left side so you add +5 to both side

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so 5 disappears on left and +5 appears on right

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Okay. but that equals 12.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0whatever you do on left you MUST do same on right to keep equation same

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i know that. ahh seee. thaats why i was like huh? lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0u got me confused rii there. its cool tho

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so plug in y= 12/10 to find x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it doesn't matter if it's on top or bottom

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0^^ that's the correct form

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ahhhhh i seee. so the answer is one solution.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there's only one solution for y and one for x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i know. but its asking me how many solutions. one two or no solutions

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have this other one. i have to find the ordered pairs. let me see if i can do it. 3x + 5y = 4 5x +5y = 60

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i'm not sure what the question is asking?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there can be infinite combination of x and y and it'll give you those answers

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it says give the ordered pairs that satisfies the system of equations

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well for the other one that your talking about.... it was asking WHAT IS THE NUMBER OF SOLUTIONS TO THE SYSTEM? and i put ONE SOLUTION

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0theres another choice that says INFINITELY MANY SOLUTIONS

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think it may be asking for just x and y like (x, y)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0let me see if i can do the other one.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i did 5x ( 3x + 5y ) +5y = 60

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no you have to solve for y first

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then you plug it in like you did

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so thats how im suppose set it up rii?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i'm not sure what you did

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you first either solve for x or y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then plug in the result to the second equation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i want to solve for X

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so how do i set it up?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.05[(5y  4)(1/3)] +5y = 60 the bracket [ ] is the x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now you only have one variable y in your equation since we plugged in for x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0where did one third come from?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait let me get this straightt....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i just plugged in for x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so now that we have our equation we have to distribute the 5 to the perenthesis (5y4) correct?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can do that then divide everything by 3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i can distribute 5 to 1/3 righT?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i can distribute 5 to 1/3 righT?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i can distribute 5 to 1/3 righT?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i can distribute 5 to 1/3 righT?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i can distribute 5 to 1/3 righT?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i can distribute 5 to 1/3 righT?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i can distribute 5 to 1/3 righT?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i can distribute 5 to 1/3 righT?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i can distribute 5 to 1/3 righT?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you're not distributing since (1/3) is its own. you simply multiply

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so what i shud have is [ (25y20) (1/3) ]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0[ (25y20) (1/3) ] + 5y = 60

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah then solve for y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now you have to distribute (1/3)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im a little confused. so right this is what i have...... [ (25y20) (1/3) ] + 5y = 60 5y  5y [ (20y 20) (1/3) ] = 60

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you don't want to move 5y to other side because you still have 25y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you want to move 20(1/3) to right

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then combine 25y(1/3) + 5y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you may want to use calculator

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so multiply 20/2 times 1/3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0remember we're trying to solve for y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait ignore that.. typo

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so multiply 20/1 times 1/3 then combien 25y times 1/3 + 5y then combine like terms so you'd end up with 30y (1/3)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you first distribute (1/3) to 25y and 20

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so it's 25y(1/3) + 5y = 60 + 20(1/3)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y(25(1/3) + 5) = 60 + 20(1/3) y = 60 + 20(1/3) / (25(1/3) + 5)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it looks real messy b/c i didn't simplify anything

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[y = 60 + 20(1/3)\div (25(1/3) + 5)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so now im gunna distribute 20 (1/3) and 25 (1/3)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it's just 20/3 and 25/3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can multiply by (1/3) or just divide by 3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0where'd that come from

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wowww. what a retardd.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry im a little bit slow and dumb

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0math is rlly not my thing.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Omgg. thank you so much! you have no idea how much you've helped me!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0np just remember to isolate x or y, whichever is easier. then plug that into the other equation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank youu! but the bad thing is, that on my worksheet, theres different types of problems. they never stick to one thing.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah, all you can do is practice. good luck

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah. thank youu! im sure ill do good on my state exam! thanks alot!
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