anonymous
  • anonymous
what is the number of solutions to the system? x + y = -1 5x - 5y = 7
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
someone please help me! i dont get this
M
  • M
solve for x then plug it in the second equation
anonymous
  • anonymous
so i would set it up like x + y = -1 = 5x - 5y = 7 ?

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More answers

M
  • M
x = -1 - y 5(-1 - y) -5y = 7 then you'll know what y is
M
  • M
if you know y then you can plug in y to first equation and find out what x is
anonymous
  • anonymous
wait let me write this down and try to do that
M
  • M
-5 - 5y -5y = 7 -10y = 14 y = -14/10
M
  • M
when you have two unknown (here x and y) then you always want to solve for x or y, then plug it into the other equation so you're working with just one unknown variable
anonymous
  • anonymous
ok i get the -10 y part. buy what about the -5 and where did 14 come from?
anonymous
  • anonymous
ahhh. isee.
M
  • M
you try to get y on left and everything else on right
anonymous
  • anonymous
yeah but you left -5 out. what did you do with it? and where did 14 come from?
M
  • M
you move -5 to right side of = sign
M
  • M
you want to get rid of -5 on left side so you add +5 to both side
M
  • M
so -5 disappears on left and +5 appears on right
anonymous
  • anonymous
Okay. but that equals 12.
M
  • M
whatever you do on left you MUST do same on right to keep equation same
M
  • M
sorry it's 12 :)
M
  • M
12/10
anonymous
  • anonymous
i know that. ahh seee. thaats why i was like huh? lol
anonymous
  • anonymous
u got me confused rii there. its cool tho
M
  • M
so plug in y= -12/10 to find x
anonymous
  • anonymous
isnt it 12/-10 ?
M
  • M
it doesn't matter if it's on top or bottom
M
  • M
it's (-1) (12/10)
M
  • M
^^ that's the correct form
anonymous
  • anonymous
ahhhhh i seee. so the answer is one solution.
M
  • M
there's only one solution for y and one for x
M
  • M
answer is a fraction
anonymous
  • anonymous
i know. but its asking me how many solutions. one two or no solutions
anonymous
  • anonymous
i have this other one. i have to find the ordered pairs. let me see if i can do it. -3x + 5y = 4 5x +5y = 60
M
  • M
i'm not sure what the question is asking?
M
  • M
there can be infinite combination of x and y and it'll give you those answers
anonymous
  • anonymous
it says give the ordered pairs that satisfies the system of equations
anonymous
  • anonymous
well for the other one that your talking about.... it was asking WHAT IS THE NUMBER OF SOLUTIONS TO THE SYSTEM? and i put ONE SOLUTION
anonymous
  • anonymous
theres another choice that says INFINITELY MANY SOLUTIONS
M
  • M
i think it may be asking for just x and y like (x, y)
M
  • M
so just one solution
anonymous
  • anonymous
yeah it is.
anonymous
  • anonymous
Okay. thanks.
anonymous
  • anonymous
let me see if i can do the other one.
anonymous
  • anonymous
i have a question
anonymous
  • anonymous
i did 5x ( -3x + 5y ) +5y = 60
M
  • M
no you have to solve for y first
M
  • M
y = (1/5)(3x +4)
M
  • M
then you plug it in like you did
anonymous
  • anonymous
so thats how im suppose set it up rii?
M
  • M
i'm not sure what you did
M
  • M
you first either solve for x or y
M
  • M
then plug in the result to the second equation
anonymous
  • anonymous
i want to solve for X
anonymous
  • anonymous
so how do i set it up?
M
  • M
x = (5y - 4)(1/3)
M
  • M
5[(5y - 4)(1/3)] +5y = 60 the bracket [ ] is the x
M
  • M
now you only have one variable y in your equation since we plugged in for x
anonymous
  • anonymous
where did one third come from?
anonymous
  • anonymous
wait let me get this straightt....
M
  • M
i just plugged in for x
anonymous
  • anonymous
ahh okay
anonymous
  • anonymous
so now that we have our equation we have to distribute the 5 to the perenthesis (5y-4) correct?
M
  • M
you can do that then divide everything by 3
anonymous
  • anonymous
i can distribute 5 to 1/3 righT?
anonymous
  • anonymous
i can distribute 5 to 1/3 righT?
anonymous
  • anonymous
i can distribute 5 to 1/3 righT?
anonymous
  • anonymous
i can distribute 5 to 1/3 righT?
anonymous
  • anonymous
i can distribute 5 to 1/3 righT?
anonymous
  • anonymous
i can distribute 5 to 1/3 righT?
anonymous
  • anonymous
i can distribute 5 to 1/3 righT?
anonymous
  • anonymous
i can distribute 5 to 1/3 righT?
anonymous
  • anonymous
i can distribute 5 to 1/3 righT?
M
  • M
you're not distributing since (1/3) is its own. you simply multiply
anonymous
  • anonymous
srry about that
anonymous
  • anonymous
so what i shud have is [ (25y-20) (1/3) ]
anonymous
  • anonymous
[ (25y-20) (1/3) ] + 5y = 60
M
  • M
yeah then solve for y
M
  • M
now you have to distribute (1/3)
anonymous
  • anonymous
im a little confused. so right this is what i have...... [ (25y-20) (1/3) ] + 5y = 60 -5y - 5y [ (20y- 20) (1/3) ] = 60
M
  • M
no
M
  • M
you don't want to move 5y to other side because you still have 25y
M
  • M
you want to move 20(1/3) to right
M
  • M
then combine 25y(1/3) + 5y
M
  • M
you may want to use calculator
anonymous
  • anonymous
so multiply -20/2 times 1/3
M
  • M
remember we're trying to solve for y
anonymous
  • anonymous
wait ignore that.. typo
anonymous
  • anonymous
so multiply 20/1 times 1/3 then combien 25y times 1/3 + 5y then combine like terms so you'd end up with 30y (1/3)
M
  • M
no
M
  • M
you first distribute (1/3) to 25y and -20
M
  • M
so it's 25y(1/3) + 5y = 60 + 20(1/3)
M
  • M
y(25(1/3) + 5) = 60 + 20(1/3) y = 60 + 20(1/3) / (25(1/3) + 5)
M
  • M
it looks real messy b/c i didn't simplify anything
M
  • M
\[y = 60 + 20(1/3)\div (25(1/3) + 5)\]
anonymous
  • anonymous
so now im gunna distribute 20 (1/3) and 25 (1/3)
M
  • M
no you just multiply
M
  • M
it's just 20/3 and 25/3
M
  • M
you can multiply by (1/3) or just divide by 3
anonymous
  • anonymous
500\3
M
  • M
where'd that come from
anonymous
  • anonymous
wowww. what a retardd.
anonymous
  • anonymous
sorry im a little bit slow and dumb
anonymous
  • anonymous
math is rlly not my thing.
M
  • M
\[200/3 \div 40/3\]
M
  • M
so it's 200/3
M
  • M
i mean 200/40
M
  • M
= 5
anonymous
  • anonymous
y = 5
M
  • M
yeah
anonymous
  • anonymous
x=7
M
  • M
yeah
anonymous
  • anonymous
Omgg. thank you so much! you have no idea how much you've helped me!
M
  • M
np just remember to isolate x or y, whichever is easier. then plug that into the other equation
anonymous
  • anonymous
thank youu! but the bad thing is, that on my worksheet, theres different types of problems. they never stick to one thing.
M
  • M
yeah, all you can do is practice. good luck
anonymous
  • anonymous
yeah. thank youu! im sure ill do good on my state exam! thanks alot!
M
  • M
bye :)

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