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anonymous
 5 years ago
@Yuki (or whoever gets to it first) so would you use the same techniques you were showing me for this one? it is in an attachment >.< sowee im confused... :P
anonymous
 5 years ago
@Yuki (or whoever gets to it first) so would you use the same techniques you were showing me for this one? it is in an attachment >.< sowee im confused... :P

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the first one is the equation your simplifying the next 3 are the options :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Eh, I would just factorise the first term, then multiply by the inverse of \[n+4 / n3\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So the first term reduces to (n+4)^2/(n3)^2 after factorising then you just multiply that by (n3)/(n+4) which cancels the first to (n+4)/(n3)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ahhh i see i would have gone with C i wish there were a quicker easier way to find the answers to these things that werent so dang complicated!! :P lol but thanks a bunch just helped me slot!! :D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so then the answer to this one would be : wait here i will attach them can u do the last two with me? pls? :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OK so factorise (n^2 + 3n + 2) to (n+2)(n+1), so it becomes \[((n+2)(n+1))\div2\] then multiply that by the reciprocal of (n+1)/(2(n+2)) which is 2(n+2) / (n+1) , both the 2s cancel and the (n+1)s cancel so its just (n+2)^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ahhhh alright i see the "pattern" or whatever lol okie dokie last one and its on long division UGH :P i stil cant get the hang of it :P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Option A = x + 5 Option D = x  7

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OK well can you do long division? Kinda hard to show it on here but I can try

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0:P i hate long division URGHHHH

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so do you think you could attach the steps?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Lol x  9 ______________ x+7/x^2  2x  30 x^2 + 7x  9x  30 9x  63  33 < remainder so it's x  9 + 33/(x+7)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok im pretty sure i get it now, well more than i got it before :) lol thanks :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0http://www.youtube.com/watch?v=3ULXhiJqlPs&feature=relmfu http://www.youtube.com/watch?v=l6_ghhd7kwQ&feature=channel_video_title

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i always get so wrapped up in the solving underneath the division thing i forget about above it ^^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah.. I remember doing long division of polynomials last term, it's annoying cause I never used to use long division in lower school I just did the divisions in my head so I had no idea how to do long division. Good luck and you're welcome..
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