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anonymous

  • 5 years ago

Solve 2^x-1=3^2x

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  1. anonymous
    • 5 years ago
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    \[2^{x-1}=3^{2x}\]

  2. anonymous
    • 5 years ago
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    im pretty sure you have to make the equation look like this : 2x^2 - 3x^2 = 1(or -1 not sure) Then you wold solve it normal do u kno how to do tht? :)

  3. anonymous
    • 5 years ago
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    No, you have to use logs to solve it, which I can't do.

  4. anonymous
    • 5 years ago
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    Ohhhh alright my bad soweee :)

  5. anonymous
    • 5 years ago
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    take the natural log, or log base anything, of each side you get: (x-1)ln(2) = 2xln(3)

  6. anonymous
    • 5 years ago
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    Then where do I go from there?

  7. anonymous
    • 5 years ago
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    get all the x's on one side. xln(2) - ln(2) = 2xln(3) xln(2) - 2xln(3) = ln(2) x(ln(2) - ln(3^2) = ln(2) then use another property of logs: ln(a) - ln(b) = ln(a/b) x(ln(2/9) = ln(2) x = ln(2)/ln(2/9)

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