anonymous
  • anonymous
On the moon the acceleration due to gravity is 1.6 metres per second squared (approximately 1 6 th of the value on earth). Standing on top of a ladder, 5 metres up, the astronaut throws a ball up vertically into the air with velocity 2m/s. How long does it take to reach the ground? How long would it take to reach the ground if the same experiment were done on earth?
Mathematics
katieb
  • katieb
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
look in google
anonymous
  • anonymous
lol
anonymous
  • anonymous
THAT DOESN'T HELP!

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
I have an answer, but I am not entirely sure if it's correct or not. I'll write it down anyway.
anonymous
  • anonymous
go for it
anonymous
  • anonymous
\[\Delta x=v_i t+{1 \over 2}at^2\], where delta x=-5 (the change in the position), v_i=2m/s and a=-1.6m/s^2. Substituting them in the equation gives: \[-5=2t+{1 \over 2}(-1.6)t^2 \implies 0.8t^2-2t-5=0\]
anonymous
  • anonymous
Solve the quadratic equation for t, you get one positive value for t. That's t=4.05 sec
anonymous
  • anonymous
Do you have the answer, or choices?
anonymous
  • anonymous
i only got to having to use the quadratic equation, i didn't realise i had to use the quadratic equation
anonymous
  • anonymous
You can just do it in your calculator.
anonymous
  • anonymous
yeah i just had to recognise that cause i think i'm meant to show working
anonymous
  • anonymous
the quadratic formula is your personal picture yo :P
anonymous
  • anonymous
yeah, cause i m having maximum trouble with it :)
anonymous
  • anonymous
LOL!

Looking for something else?

Not the answer you are looking for? Search for more explanations.