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anonymous

  • 5 years ago

On the moon the acceleration due to gravity is 1.6 metres per second squared (approximately 1/6th of the value on earth). Standing on top of a ladder, 5 metres up, the astronaut throws a ball up vertically into the air with velocity 2m/s. How long does it take to reach the ground? How long would it take to reach the ground if the same experiment were done on earth?

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  1. anonymous
    • 5 years ago
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    I would say use the kinematic equations to solve them. How where a= g/6 and g is earths gravity. In this case I would break it into two problems. How high does it go and how long does it take to reach the maximum height. then solve how long it takes to reach the ground. If you have no clue what to do post it. Finding this can be tedious.

  2. anonymous
    • 5 years ago
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    \[s_f = v_0t+(1/2)g_{moon}t^2 +5\] because the ball's final height is 0meters, sf = 0meters use quadratic equation to solve for t.

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