anonymous
  • anonymous
Can someone please explain how to use the half-angle formula to solve sin Pi/8?
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
hi jake are yo there? do yo know the formula for half angle ?
anonymous
  • anonymous
sin(x/2)=sqrt((1-cosx)/2)
anonymous
  • anonymous
i think it is sin alpha/2=the square root of 1-cos alpha/2. it looks really weird having to type it out

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anonymous
  • anonymous
so alpha is just x. that makes more sense
anonymous
  • anonymous
yes ..ok you can find x here by eqating x/2=pi/8
anonymous
  • anonymous
i got x=.7853...
anonymous
  • anonymous
ok use that for the right hand side
anonymous
  • anonymous
I'm sorry I don't know what the next step is..
anonymous
  • anonymous
ok here it is ill give you it more better
anonymous
  • anonymous
sin((pi/4*2)=sqrt(1-cos(pi/4)/2) =sqrt((1-(sqrt2)/2))2 =sqrt((2-sqrt2))/4 =sqrt(.1464466) =.38268
anonymous
  • anonymous
so pi/4 became your x here
anonymous
  • anonymous
does it make sense ?
anonymous
  • anonymous
yes that is making sense. i'm just trying to redo it on paper to see if i can get the same answer. Thank you very much
anonymous
  • anonymous
ok wc jake
anonymous
  • anonymous
you got it....good luck
anonymous
  • anonymous
Thanks!
anonymous
  • anonymous
k,yo have any more question or anymore prob i can help u maybe?
anonymous
  • anonymous
are you not busy?
anonymous
  • anonymous
not really lol
anonymous
  • anonymous
haha well i'm in pre cal obviously and not very good at it. i have this problem: if sin theta=3/5, and tan theta<0 then in what quadrant is the point (cos theta, sin theta)?
anonymous
  • anonymous
ok here we can put theta =x...therefore tanx=sinx/cosx so x=3/5 its in the first quadrant..but tanx is negative) so it is obvius that sin 3/5 is in the first quadrant and the cosx is in the 3rd quadrant
anonymous
  • anonymous
cos x in the third quadrant is negative sign
anonymous
  • anonymous
tanx <0 means tanx is a negatinve sign
anonymous
  • anonymous
Wow thank you for your help mark

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