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anonymous
 5 years ago
Can someone please explain how to use the halfangle formula to solve sin Pi/8?
anonymous
 5 years ago
Can someone please explain how to use the halfangle formula to solve sin Pi/8?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hi jake are yo there? do yo know the formula for half angle ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sin(x/2)=sqrt((1cosx)/2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think it is sin alpha/2=the square root of 1cos alpha/2. it looks really weird having to type it out

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so alpha is just x. that makes more sense

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes ..ok you can find x here by eqating x/2=pi/8

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok use that for the right hand side

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm sorry I don't know what the next step is..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok here it is ill give you it more better

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sin((pi/4*2)=sqrt(1cos(pi/4)/2) =sqrt((1(sqrt2)/2))2 =sqrt((2sqrt2))/4 =sqrt(.1464466) =.38268

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so pi/4 became your x here

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes that is making sense. i'm just trying to redo it on paper to see if i can get the same answer. Thank you very much

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you got it....good luck

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0k,yo have any more question or anymore prob i can help u maybe?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0haha well i'm in pre cal obviously and not very good at it. i have this problem: if sin theta=3/5, and tan theta<0 then in what quadrant is the point (cos theta, sin theta)?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok here we can put theta =x...therefore tanx=sinx/cosx so x=3/5 its in the first quadrant..but tanx is negative) so it is obvius that sin 3/5 is in the first quadrant and the cosx is in the 3rd quadrant

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0cos x in the third quadrant is negative sign

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0tanx <0 means tanx is a negatinve sign

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Wow thank you for your help mark
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