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hi jake are yo there? do yo know the formula for half angle ?
i think it is sin alpha/2=the square root of 1-cos alpha/2. it looks really weird having to type it out
so alpha is just x. that makes more sense
yes ..ok you can find x here by eqating x/2=pi/8
i got x=.7853...
ok use that for the right hand side
I'm sorry I don't know what the next step is..
ok here it is ill give you it more better
sin((pi/4*2)=sqrt(1-cos(pi/4)/2) =sqrt((1-(sqrt2)/2))2 =sqrt((2-sqrt2))/4 =sqrt(.1464466) =.38268
so pi/4 became your x here
does it make sense ?
yes that is making sense. i'm just trying to redo it on paper to see if i can get the same answer. Thank you very much
ok wc jake
you got it....good luck
k,yo have any more question or anymore prob i can help u maybe?
are you not busy?
not really lol
haha well i'm in pre cal obviously and not very good at it. i have this problem: if sin theta=3/5, and tan theta<0 then in what quadrant is the point (cos theta, sin theta)?
ok here we can put theta =x...therefore tanx=sinx/cosx so x=3/5 its in the first quadrant..but tanx is negative) so it is obvius that sin 3/5 is in the first quadrant and the cosx is in the 3rd quadrant
cos x in the third quadrant is negative sign
tanx <0 means tanx is a negatinve sign
Wow thank you for your help mark