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anonymous
 5 years ago
find the vertex of the parabola: f(x)= x^2x+1
anonymous
 5 years ago
find the vertex of the parabola: f(x)= x^2x+1

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0a=1 b=1 c=1 x = b/2a x= (1)/2(1) = 1/2 y = (1/2)^2  1/2 +1 y = 1/4  1/2 +1 y = 3/4 vertex = (1/2, 3/4) Also you could use completing the square to put it in vertex form y = a(xh)^2 +k where vertex = (h,k) take half of b b/2 = 1/2 this will be the "h" part now square it and subtract from c (1/2)^2 = 1/4 1  1/4 = 3/4 y = (x 1/2)^2 + 3/4 vertex = (1/2, 3/4)
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