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anonymous

  • 5 years ago

Please help me to solve this equation : (2x^3+5x^2-22x+10)/(2x-3)

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  1. anonymous
    • 5 years ago
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    What are you solving for? When the expression equals 0?

  2. anonymous
    • 5 years ago
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    They just ask to perform the indicated operations

  3. anonymous
    • 5 years ago
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    x^2 + 4x - 5 Remainder -5

  4. anonymous
    • 5 years ago
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    Could you please show me the step?

  5. anonymous
    • 5 years ago
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    Do you know how to long divide?

  6. anonymous
    • 5 years ago
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    no, i don't know how to do it

  7. anonymous
    • 5 years ago
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    A long process... Here goes.

  8. anonymous
    • 5 years ago
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    2x times what is 2x^3 ... the answer is x^2 so that is what you put up first. Once you put something on top, you multiply it by what is to the left of the 2x^3 you distribute to accomplish this. Then draw a line under what you just wrote. x^2 ----------------------- 2x - 3 |2x^3 + 5x^2 - 22x + 10 2x^3 - 3x^2 ------------

  9. anonymous
    • 5 years ago
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    Then you change the signs on the bottom and add. And then bring down the next term. Start again... same steps.... 2x times what is 8x^2... answer 4x.. I will put that on top x^2 ----------------------- 2x - 3 |2x^3 + 5x^2 - 22x + 10 -2x^3 + 3x^2 ----------- 8x^2 - 22x

  10. anonymous
    • 5 years ago
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    x^2 + 4x - 5 Remainder -5 ----------------------- 2x - 3 |2x^3 + 5x^2 - 22x + 10 -2x^3 + 3x^2 ----------- 8x^2 - 22x - 8x^2 + 12x ----------- -10x + 10 +10x - 15 --------- -5 2x times what is -10x... answer -5

  11. anonymous
    • 5 years ago
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    I got it...thanks so much

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