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anonymous
 5 years ago
How do you find the equation of a line that is perpendicular to the line y=1/8x+9, containing the point (5, 0)?
anonymous
 5 years ago
How do you find the equation of a line that is perpendicular to the line y=1/8x+9, containing the point (5, 0)?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0A perpendicular line means its slope is reciprocated and negated. The slope of the original line is 1/8, so the slope of the new line is 8, giving you: \[y = 8x+b\] To orient the line such that it passes through the point (5, 0), insert those values into the new equation and solve for b: \[0 = (8)(5)+b\] 40 = b Thus the perpendicular line that passes through (5, 0) is: \[y = 8x + 40\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If you are still here, I have a question. The equation I was given already had 9 as the value of b. So I don't think that we would be solving for b..
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