How do you find the equation of a line that is perpendicular to the line y=1/8x+9, containing the point (5, 0)?

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How do you find the equation of a line that is perpendicular to the line y=1/8x+9, containing the point (5, 0)?

Mathematics
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A perpendicular line means its slope is reciprocated and negated. The slope of the original line is 1/8, so the slope of the new line is -8, giving you: \[y = -8x+b\] To orient the line such that it passes through the point (5, 0), insert those values into the new equation and solve for b: \[0 = (-8)(5)+b\] 40 = b Thus the perpendicular line that passes through (5, 0) is: \[y = -8x + 40\]
If you are still here, I have a question. The equation I was given already had 9 as the value of b. So I don't think that we would be solving for b..

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