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anonymous

  • 5 years ago

Problem: b is any real such that |b| < 1. relation f is defined on any real for which |x| < 1 such that f(x) = (x - b) / (bx - 1). Is this a function??

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  1. amistre64
    • 5 years ago
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    plug in b=1/2 and see :)

  2. amistre64
    • 5 years ago
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    2x-1 ----- x -2

  3. amistre64
    • 5 years ago
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    looks functiony

  4. amistre64
    • 5 years ago
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    for any given value of x; you only produce 1 y so yeah :)

  5. amistre64
    • 5 years ago
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    barring x=2 of course

  6. dumbcow
    • 5 years ago
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    you can also show f(x) is defined on every point where |x|<1 f(x) is only undefined if bx-1 =0 bx-1 =0 bx=1 b=1/x since |x|<1 the reciprocal |1/x |>1 but |b| is defined as less than 1 thus b can not equal 1/x and f(x) is defined at every point in the interval |x|<1

  7. amistre64
    • 5 years ago
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    how does that define a function? sounds more like continuity.

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