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anonymous

  • 5 years ago

The sum of the digits of a two-digit number is 12.If the digits are reversed,the new number is 18 more than the original number.Find the original number.

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  1. anonymous
    • 5 years ago
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    x+y = 12 10y+x = 10X + y +18

  2. anonymous
    • 5 years ago
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    where x and y are the 2 digits

  3. anonymous
    • 5 years ago
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    x+y=12 x+10y=y+10x+18 x-y=2. gives u x=7,y=5 the no is 57

  4. anonymous
    • 5 years ago
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    jab ek banda reply kar chuka to kyun sab zor lagate ho yaar?

  5. anonymous
    • 5 years ago
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    TLet the original number be 10x + (12-x) Then on reversing it becomes 10(12-x) + x Atq 10(12-x) + x = 10x + (12-x) + 18 Solve this, get value of x and then get the two numbers

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