anonymous
  • anonymous
In the coordinate plan the vertices of Triangle ABC are A(-4, -3), B(2, 5), and C(8, -3), and the coordinates of Triangle XYZ(-10,-7), Y(-7,-3) and Z(-4,-7) Prove that Triangle ABC ~ Triangle XYZ There is a graph including on the question as well.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
you can find the sides of the tringles... and you will see that AB=10. BC=10. AC=12. XY=5, YZ=5, ZX=6. so the sides are in the ratio 2:1 so ABC~XYZ
anonymous
  • anonymous
Oh I see, but how would I explain that on paper. And to find the sides I use distance formula correct
anonymous
  • anonymous
to find the side use the formula \[\sqrt{(x _{1}-x _{2})^{2}+(y _{1}-y _{2})^{2}}\]

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anonymous
  • anonymous
Alright Thank You
anonymous
  • anonymous
But how do I explain the ratio part, I don't understand the ratio part at all.
anonymous
  • anonymous
see AB/XY =BC/YZ =CA/ZX=2 i.e. the sides are in the same ratio...
anonymous
  • anonymous
I guess I kinda do, but how do I say ABC ~ XYZ I use the Ratio 2:1 to Say that?

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