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anonymous
 5 years ago
How do I find the regions for the triple integral to calculate the mass of the the volume between the paraboloid x^2+y^2 = 2az and the sphere x^2+y^2+z^2=3a^2
with a density of d(x,y,z)=x^2+y^2+z^2?
anonymous
 5 years ago
How do I find the regions for the triple integral to calculate the mass of the the volume between the paraboloid x^2+y^2 = 2az and the sphere x^2+y^2+z^2=3a^2 with a density of d(x,y,z)=x^2+y^2+z^2?

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1is that similar to finding the solution to a system of equations in order to compute that volume of a solid?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I didn't quite understand what you mean... To be more clear, I must find out the volume between the two objects, then calculate it's mass. (oh and a>0)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1oh... so the sphere and the paraboloid arent intersecting are they...lol. Wrong concept on my part :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes they are intersecting, and I must find that volume.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1when two curves meet and we want to find the area between them, we integrate the bounds between where they meet; is that something we can do to the sphere and parabaloid?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1when does: x^2 +y^2 2az = x^2 +y^2 +z^23az^2 ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it intersects in a circle in the plane z=a

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1that circle is one bound of the interecting shapes then; do we have an x bound and a ybound yet?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1we are trying, if i see it correctly, find the area that is scooped out of an ice cream container :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1area means volume lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1there should be an upper and lower bound of all three dimensions

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1if we could extablish a cross section; could we spin it to find the volume of the solid created by the rotation about an axis?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Unusually complicated. I would try\[\int\limits_{0}^{2\pi}\int\limits_{r ^{2}/2a}^{\sqrt{3a ^{2}r ^{2}}}\int\limits_{a \sqrt{2(3a ^{2}1)}}^{a ^{2\sqrt{6}}}r ^{3+z ^{2}drdzd \theta}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thanks guys, I'll give it a try. Although I'm not so sure about the limits of dr
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