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anonymous
 5 years ago
(2x^(4)x^(3)+1)/(x+3) Use remainder theorem to find the remainder.
Please show all work.
Thanks.
anonymous
 5 years ago
(2x^(4)x^(3)+1)/(x+3) Use remainder theorem to find the remainder. Please show all work. Thanks.

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2the remainder thrm just says that there is an added remaineder to the answer ;)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2we divide these like they were any other numbers.... division is division regardless of what you divide..

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2the key is to remember how long division is done; or use synthetic division

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have to use long division but im confused because in order to devide i have to 2x^4 times (x+3) then it would be 2x^4 x^3 over 2x^4 6x^3 and then i got confused

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2we can work thru that are you remembering to subtract your answers?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what do you mean exactly u mean 2x^4 2x^4 = 0 and then x^3  (6x^3)?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.22x^3 < 2x^3(x+3)= (2x^4+6x^3), but we subtract this result  to get our next round...... x+3 2x^4 x^3 +1 2x^4 6x^3  7x^3 +1

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2remember how to do it with numbers? same thing: 3 < 6(3) = 18....what do we do with the 18?  6 19 18 < we subtract it....  1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok i see where i messed up originally now we times (x+3) by 7x^2? and then work the problem?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.22x^3 7x^2  x+3 2x^4 x^3 +1 2x^4 6x^3  7x^3 +1 +7x^3 +21x^2  21x^2 +1 < whatever doesnt cancel out gets brought down

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2the next number need to be the same as this bottom first number...or at least get to equal it.... we need a 21; and x*x=x^2 so....... 21x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait never mind it needs to be by 21x^2?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.22x^3 7x^2 +21x  x+3 2x^4 x^3 +1 2x^4 6x^3  7x^3 +1 +7x^3 +21x^2  21x^2 +1 21x^2 63x  63x +1

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2do you understand that we are subtracting the result?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now just (x+3) times 63? and yes sir/ma'am

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.063 right so we get 63x+189?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and then remainder is 190?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2thats right :) now... 63x  (63x) = 0 right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.22x^3 7x^2 +21x 63x  x+3 2x^4 x^3 +1 2x^4 6x^3  7x^3 +1 +7x^3 +21x^2  21x^2 +1 21x^2 63x  63x +1 +63x +189  190 < remainder :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2synthetic is similar, but we already work with an opposite so we add stuff.... (x+3)..x=3 32 1 0 0 1 0 6 21 63 189  2 7 +21 63 190 < remainer 190 ^^^^^^^^^^^ 2x^3 7x^2 +21x 63
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