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(-2(1-t), -1(1-t)) +(t, 2t)
ordered pairs.. what i guessed
=(-2+2t+t,-1+t+2t) =(-2+3t, -1+3t)
i cant make out what the quaestion is asking for lol
maybe its the addition of 2 vectors from initial points? or the distance between then or something....
scalars and addition....ok got it
it is in line integral notes
it is vector notation. the () are equations to calculate the scalar functions of each vector; hence(1-t) and (t) cahnge the size of the arrow that represents each vector..
6<2,3> is an arrow from the origin to a point (2,3); the scalar says to multiply those values by 6 in this case... <6(2),6(3)> = <12,18>which is an arrow from the origin to a point (12,18)
(1-t)<-2,-1> means to scale the vector by whats in the (): <-2(1-t),-1(1-t)> = <-2+t,-1+t>
vector t<1,2> is scaled to : <1t,2t>.... now add the vectors together
<-2+t, -1+t> < 1t , 2t > ------------- <-2t+2t, -1+3t>
gotta read thru the typos lol
now u really need some vitamin :P
-2(1-t) why that's answer isn't -2+2t :S you write -2+t
oh yes... i mistake, u r right
you gotta read it for what it is; not for the typos in it lol
if i type 2+6=9....you gotta have sense enough to understand that im an idiot and look past the fat fingers to the message itself lol
how sweet ..... suppose u r a teacher, n marking the scripts, underlining the mistakes, n get the same reply from the student ;)
just kidding :P
here most of the things must be understood :)
i think my question can't replied but thanks
oh no... u may ask where r u confused
just go on :)
If you know about vectors and scalars of vectors and addition of vectors; then the question is answered...