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anonymous

  • 5 years ago

r(t)=(1-t)<-2,-1>+t<1,2> the answer is < -2+3t,-1+3t> but i can't understand how can we do this calculation

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  1. amistre64
    • 5 years ago
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    multiply ?

  2. anonymous
    • 5 years ago
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    (-2(1-t), -1(1-t)) +(t, 2t)

  3. anonymous
    • 5 years ago
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    no

  4. anonymous
    • 5 years ago
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    ordered pairs.. what i guessed

  5. anonymous
    • 5 years ago
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    =(-2+2t+t,-1+t+2t) =(-2+3t, -1+3t)

  6. amistre64
    • 5 years ago
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    i cant make out what the quaestion is asking for lol

  7. amistre64
    • 5 years ago
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    maybe its the addition of 2 vectors from initial points? or the distance between then or something....

  8. amistre64
    • 5 years ago
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    scalars and addition....ok got it

  9. anonymous
    • 5 years ago
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    it is in line integral notes

  10. amistre64
    • 5 years ago
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    it is vector notation. the () are equations to calculate the scalar functions of each vector; hence(1-t) and (t) cahnge the size of the arrow that represents each vector..

  11. amistre64
    • 5 years ago
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    6<2,3> is an arrow from the origin to a point (2,3); the scalar says to multiply those values by 6 in this case... <6(2),6(3)> = <12,18>which is an arrow from the origin to a point (12,18)

  12. amistre64
    • 5 years ago
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    (1-t)<-2,-1> means to scale the vector by whats in the (): <-2(1-t),-1(1-t)> = <-2+t,-1+t>

  13. amistre64
    • 5 years ago
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    vector t<1,2> is scaled to : <1t,2t>.... now add the vectors together

  14. amistre64
    • 5 years ago
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    <-2+t, -1+t> < 1t , 2t > ------------- <-2t+2t, -1+3t>

  15. amistre64
    • 5 years ago
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    gotta read thru the typos lol

  16. anonymous
    • 5 years ago
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    now u really need some vitamin :P

  17. anonymous
    • 5 years ago
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    -2(1-t) why that's answer isn't -2+2t :S you write -2+t

  18. anonymous
    • 5 years ago
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    oh yes... i mistake, u r right

  19. amistre64
    • 5 years ago
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    you gotta read it for what it is; not for the typos in it lol

  20. amistre64
    • 5 years ago
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    if i type 2+6=9....you gotta have sense enough to understand that im an idiot and look past the fat fingers to the message itself lol

  21. anonymous
    • 5 years ago
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    how sweet ..... suppose u r a teacher, n marking the scripts, underlining the mistakes, n get the same reply from the student ;)

  22. anonymous
    • 5 years ago
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    just kidding :P

  23. anonymous
    • 5 years ago
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    here most of the things must be understood :)

  24. amistre64
    • 5 years ago
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    lol

  25. anonymous
    • 5 years ago
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    i think my question can't replied but thanks

  26. anonymous
    • 5 years ago
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    oh no... u may ask where r u confused

  27. anonymous
    • 5 years ago
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    just go on :)

  28. amistre64
    • 5 years ago
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    If you know about vectors and scalars of vectors and addition of vectors; then the question is answered...

  29. amistre64
    • 5 years ago
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    n<x,y> + m<p,q> <nx ,ny> +<mp,mq> ---------- <nx+mp, ny+mq>

  30. anonymous
    • 5 years ago
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    thanks:D

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