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anonymous
 5 years ago
find the volume of the solid obtained by rotating about the yaxis the region bounded by the curve y=2x^2x^3 and the xaxis. How do I do this?
anonymous
 5 years ago
find the volume of the solid obtained by rotating about the yaxis the region bounded by the curve y=2x^2x^3 and the xaxis. How do I do this?

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0find the the x and y intercepts

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0y=0 at 0 and 3/2 right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0thats right lol.... i transposed that 3 dint i :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0so we have bounds of x=0 and x=2 then right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0we need to get these in terms of y to calculate the y axis spin; lets do an inverse

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0x = 2y^2 y^3 ; solve for y :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0wolfram might help with this :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0good idea. I will get back to you a little later on this I have a baseball game.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0are you sure its spun around the y axis? and not the x axis?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0let me read up on the shell method; its prolly easier with this setup..

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.02pi [S] x[f(x)] dx ; from [0,2]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0x(2x^2x^3) = 2x^3 x^4 soo... we integrate that to get; (5x^4 2x^5)/10. At 0 it is zero; so we just worry about the 2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i get 8/5 as the volume of the torus....if i did it right lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0so i am going to try this on firefox..... and it seems to be working good so far :)
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