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anonymous

  • 5 years ago

equation of bisector of acute angle between lines 3x+4y+5=0 and 12x-5y-7=0 is

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  1. anonymous
    • 5 years ago
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    u dont know this?

  2. anonymous
    • 5 years ago
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    i dont knw my ans is nt matchng

  3. anonymous
    • 5 years ago
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    frst make both the c +ve

  4. anonymous
    • 5 years ago
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    multiply the second line with -1

  5. anonymous
    • 5 years ago
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    and now as a1a2 + b1b2 is -ve

  6. anonymous
    • 5 years ago
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    L1/5 = -L2/13

  7. anonymous
    • 5 years ago
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    get it??

  8. anonymous
    • 5 years ago
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    kind of..........

  9. anonymous
    • 5 years ago
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    oh i got it where i was wrong thanx

  10. anonymous
    • 5 years ago
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    see when a1a2 + b1b2 is negtiv, the eqn where signs of both lines are opposite is the acute bisector

  11. anonymous
    • 5 years ago
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    yeah....no prob

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spraguer (Moderator)
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