anonymous
  • anonymous
An ordinary (fair) die is a cube with the numbers 1 through 6 on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of a random experiment. Compute the probability of each of the following events: Event : The sum is greater than 8 . Event : The sum is divisible by 3 or 4 (or both). Write your answers as exact fractions.....
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
10/36
anonymous
  • anonymous
what about the second event
anonymous
  • anonymous
20/36

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anonymous
  • anonymous
Are you sure about that? I think it's 6/36 for a and 12/36 for b. To get greater than 8, you need a sum of 9, 10, 11, or 12. You can get this with: 3-6 4-5 4-6 5-5 5-6 6-6 So, 6 of 36 possible combinations. For b, you can have a sum of 3, 4, 6, 8, 9, 12: 1-2 1-3 2-2 1-5 2-4 3-3 2-6 3-5 4-4 3-6 4-5 6-6 So, 12/36. Or I missed something.
anonymous
  • anonymous
Simplifies to 1/6 and 1/3.

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