An ordinary (fair) die is a cube with the numbers 1 through 6 on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of a random experiment.
Compute the probability of each of the following events:
Event : The sum is greater than 8 .
Event : The sum is divisible by 3 or 4 (or both).
Write your answers as exact fractions.....
Stacey Warren - Expert brainly.com
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Are you sure about that? I think it's 6/36 for a and 12/36 for b.
To get greater than 8, you need a sum of 9, 10, 11, or 12.
You can get this with:
So, 6 of 36 possible combinations.
For b, you can have a sum of 3, 4, 6, 8, 9, 12:
Or I missed something.