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anonymous
 5 years ago
An ordinary (fair) die is a cube with the numbers 1 through 6 on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of a random experiment.
Compute the probability of each of the following events:
Event : The sum is greater than 8 .
Event : The sum is divisible by 3 or 4 (or both).
Write your answers as exact fractions.....
anonymous
 5 years ago
An ordinary (fair) die is a cube with the numbers 1 through 6 on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of a random experiment. Compute the probability of each of the following events: Event : The sum is greater than 8 . Event : The sum is divisible by 3 or 4 (or both). Write your answers as exact fractions.....

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what about the second event

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Are you sure about that? I think it's 6/36 for a and 12/36 for b. To get greater than 8, you need a sum of 9, 10, 11, or 12. You can get this with: 36 45 46 55 56 66 So, 6 of 36 possible combinations. For b, you can have a sum of 3, 4, 6, 8, 9, 12: 12 13 22 15 24 33 26 35 44 36 45 66 So, 12/36. Or I missed something.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Simplifies to 1/6 and 1/3.
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