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anonymous

  • 5 years ago

x(x-7)=-49 ???

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  1. anonymous
    • 5 years ago
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    Okay - let's multiply out the left side. \[x ^{2}-7x=-49\] Then we'll make a traditional equation set to 0 by adding 49 to both sides: \[x ^{2}-7x+49=0\] Now we have to use the quadratic equation (because no two numbers, when multiplied by each other = 49, and when added to each other=-7) \[(-b \pm \sqrt{b ^{2}-4ac})/2a\] From our traditional equation, a=1, b=-7, and c=49 so we have \[(-(-7)\pm \sqrt{-7^{2}-4*1*49})/2*1\] That's all just numbers, so see what you can do with it..

  2. anonymous
    • 5 years ago
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    oh that way i ended up with the x's on one side and didnt know what to do afterwards :p

  3. anonymous
    • 5 years ago
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    thanks

  4. anonymous
    • 5 years ago
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    amist...did I do that right? I think I get a complex number out of that mess...

  5. amistre64
    • 5 years ago
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    you did it right :)

  6. anonymous
    • 5 years ago
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    huh?? isnt that equation i just need to put inot my calculator?

  7. amistre64
    • 5 years ago
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    there are no 'real' solutions lol

  8. anonymous
    • 5 years ago
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    oh :o

  9. amistre64
    • 5 years ago
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    sqrt(-#) is not answerable in an R^2 line up

  10. anonymous
    • 5 years ago
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    didn't seem like a complex question....I think you may have mistyped the question, MissM, because there is not a real solution to this equation, and from what I recall I am not sure it is applicable to the level of math you are studying. What class is this for?

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