Could someone tell me if my answer was correct? I will attach the equation and available answers in a comment! Its just a algebra question but im evidently unable to focus rite now >.<

- anonymous

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- anonymous

Which one is the question?

- anonymous

the one that says "ok" ^_^

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## More answers

- anonymous

I see.

- anonymous

The process is confusing me im pretty sure this is one of the lessons that i missed :P

- anonymous

So the question is to simplify:
\[{4 \over m+2}+{2 \over m-2}?\]

- anonymous

The m + 2 and m - 2 is confusing me :P And it says to Add and Simplify.

- anonymous

Good. First, what is the LCM of (m+2) and (m-2).

- anonymous

Thats the part that was confusing me ^_^ lol

- anonymous

Haha I see. Do (m+2) and (m-2) have any common factors?

- anonymous

Yep lol >.< i think urghh i should of paid attention :P and i just didnt know how to write it bc of the - and + signs >.< lol

- anonymous

Well they don't have a common factor, and because of that the LCM of them is their multiplication.

- anonymous

Ahhhhhh alright i get it so far. ^_^

- anonymous

so (m+2)(m-2)=m^2-4. That's would be our LCM.

- anonymous

That's good. Now, we have to apply this to our equation.

- anonymous

expression*

- anonymous

ohhhh haha wow ya bc since they dont have a common factors u'd multiply them together. alright.

- anonymous

Exactly.

- anonymous

That means, we will multiply the first term (top and bottom) by (m-2). and multiply the second term (top and bottom by (m+2).

- anonymous

Does that make sense?

- anonymous

Yes so far so good so then the answer would be the "ya" one? lol like my labels? :D

- anonymous

>.< i think... :P

- anonymous

\[{4 \over m+2}+{2 \over m-2}={4(m-2) \over m^2-4}+{2(m+2) \over m^2-4}={4m-8+2m+4 \over m^2-4}={6m-4 \over m^2-4}\]

- anonymous

OR as in the choices:
\[{6m-4 \over (m+2)(m-2)}\]

- anonymous

WOOOOOOOOOOOOO!!!! so i was rite huh?!?! YAY YAY YAY!!

- anonymous

lol ^_^

- anonymous

Haha Yeah you were :)

- anonymous

:) Thanks, helped my bunches! :D

- anonymous

np

- anonymous

Oh! and do you think you could help me on part of this other question? :) plesss? lol

- anonymous

so ok is the original expression?

- anonymous

You make strange names? :P

- anonymous

My question is about the denominators again so would there be common factors? >.< i got confused again :P lol and ya i am making strange names ^^

- anonymous

The same first question again, do they have common factors?

- anonymous

And yea this is the original expression .. pretty sure lol

- anonymous

and i thought they did >.< like since 3x can go into 6x.. but then i got lost arghh

- anonymous

Okay can you factor any of the two denominators?

- anonymous

No i dont think so

- anonymous

Wait which version of factoring? >.<

- anonymous

3x+5 can't be factored..
(6x+10)=2(3x+5).. right?

- anonymous

Right.

- anonymous

Okay now your LCD should be each one of the factor to be taken only one. the factors we have are (3x+5) and 2. so our LCD would 2(3x+5).

- anonymous

I don't think that was clear enough, was it?

- anonymous

Not really im sitting here repeating it over in my head going wth.... ^_^

- anonymous

LOL

- anonymous

Well, you can see that (3x+5) occur in both denominators. right?

- anonymous

after factorization*

- anonymous

Yep i see that.

- anonymous

\[{2 \over 3x+5}-{1 \over 6x+10}={2 \over 3x+5}-{1 \over 2(3x+10)}\] Right?

- anonymous

Now list all factors in both denominators.

- anonymous

I mean 2(3x+5) :)

- anonymous

Ahhhh so then i see why you would do that. But couldnt you just multiply the 3x + 5 expression by 2 and then subtract?

- anonymous

the two equations with the same denominator i mean ^^

- anonymous

Yes you could, but then you have to simplify after that.

- anonymous

that wouldn't be the simplest form.

- anonymous

Ahhh rite, ^_^ ok then go on lol

- anonymous

Well you're saying that you multiply the (3x+5) by 2, that's right. And that's what I was trying to say when I said that 2(3x+5) is the LCD. So then we keep the 6x+10 and multiply the (3x+5) term (top and bottom) by 2.

- anonymous

:)

- anonymous

ohh so the answer would be B haha wow i rly need to stop doubting myself argh :P

- anonymous

LOL thanks for the help! AGAIN ^_^

- anonymous

But you know why we can do that. That's because the denominator of the second term is nothing but 2 times the denominator of the first term.

- yuki

AnwarA, how did you make the rational expression look like that ?

- anonymous

It's 2(3x+5).. just typo :P

- yuki

all I can do is\[{a+bi}/{10a-c}\]

- yuki

how did you make it go under a long bar ?

- anonymous

lol think person means like how do u ya long bar ^^

- anonymous

Oh.. {a+bi over 10a=c}

- anonymous

And hello yuki.

- anonymous

:)

- anonymous

>.< i will never understand computer tech/ math peoples smartness :P

- anonymous

haha. I think I am the only one who does it this way :P

- yuki

\[\sqrt(b^2-4ac) \over 2a\]

- yuki

that is sooo cooooool !! I am goint to use it from now on, thanks!

- anonymous

LOL obviously not anymore!! :D and i see someone ik viewing the question but he isnt in our meeting place!! >:P lol (inside joke cant rly explain it ^^)

- anonymous

\[{\sqrt{b^2-4ac} \over 2a} \]
:P

- yuki

can you do "plus or minus" as well ?

- anonymous

Haha

- anonymous

>.< smart people arg lol

- anonymous

Yep anything

- anonymous

\[{-b \pm \sqrt{b^2-4ac} \over 2a}\]

- yuki

how did you make the sqrt top part long ?!
I have so much to learn lol

- anonymous

Haha try that yourself :P

- yuki

is there a place that have all of that written down ?

- anonymous

*sigh* so much to learn to little time lmao im jk :)

- anonymous

just use {}, with anything that you want to make long :)

- yuki

\[\sqrt{10x+b}\]

- anonymous

Hah, i think its funnay how i have no idea how the heck u guys are doing that ^^

- anonymous

\[e^{ANWAR}={1 \over \sqrt{yuki}^{dolly}}\] :P that does not mean anything by the way

- yuki

\[\int\limits _{a,b}_{b,a}\]

- anonymous

lol im above yuki hee hee!!!!

- anonymous

I am in the top, that's what matters :D

- yuki

\[\ln(\ln (x)) = 0\]

- anonymous

:P looks more like im the glue that holds everything together mwuahahaha!!!

- anonymous

take ln of both sides to bring me down :(

- yuki

\[+,- \pm \]

- yuki

Ha ! found it lo

- anonymous

You're learning :P

- yuki

\[\cos(a \pm b) = \cos(a)\cos(b) \mp \sin(a)\sin(b)\]

- anonymous

im not ^_^ LOL

- anonymous

You want to?

- anonymous

But you can't use your weird names there :P

- anonymous

yuki, whenever you use these things, rmr to thank me first

- anonymous

awww yep sure the person i am waiting for isnt talking so sure :) lol

- yuki

\[\int\limits_{a,b \int\limits_{1}^{2}}\]

- anonymous

Haha

- anonymous

whom are you waiting for? xD

- yuki

I definitely will AnwarA

- anonymous

his name starts with an I and he is rlyyyy sweet and hot and all tht jaz oh and did i mention it was u ? xD lmao

- anonymous

haha anwar is all like wat the hell.... LOL

- anonymous

Thanks buddy!! I was just kidding. I did nothing, anyone who knows that would help do that. :)

- anonymous

@dolly: LOL

- yuki

\[{a+bi \over a-bi} *{a+bi \over a-bi}\]

- anonymous

^_^

- anonymous

why do you think I was "all like what the hell"? :)

- anonymous

haha to what i said lol jeezus anwar pay attention!! >:D im jk :)

- anonymous

Haha, I read that and I wasn't "all like what the hell" at all :P

- anonymous

yuki, what grade are you at?

- anonymous

LOL then i was wrong i thought u would be ^_^ lol and prolly college or high school senior!! lol

- anonymous

I think wherever I need info about anyone in this site, I should just come straight to you. You got it all :O

- anonymous

Do you work for the CIA?

- anonymous

haha its easy i just notice the kind of math they know how to do, the way they type.. etc :) nm too it :D

- anonymous

so you are not here to gather informations about us for some agencies?

- anonymous

Uhh, no. lol That would only be extremely creepy lol

- anonymous

:) Anyway, I am off to bed. Yuki would be more of help than I am, specially that he now knows how to do the equations thing :D.

- anonymous

Bye all!!

- anonymous

LOL okie dokie nite buddaaayyyy!!! :)

- yuki

sigma

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