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anonymous
 5 years ago
Could someone tell me if my answer was correct? I will attach the equation and available answers in a comment! Its just a algebra question but im evidently unable to focus rite now >.<
anonymous
 5 years ago
Could someone tell me if my answer was correct? I will attach the equation and available answers in a comment! Its just a algebra question but im evidently unable to focus rite now >.<

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Which one is the question?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the one that says "ok" ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The process is confusing me im pretty sure this is one of the lessons that i missed :P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So the question is to simplify: \[{4 \over m+2}+{2 \over m2}?\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The m + 2 and m  2 is confusing me :P And it says to Add and Simplify.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Good. First, what is the LCM of (m+2) and (m2).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thats the part that was confusing me ^_^ lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Haha I see. Do (m+2) and (m2) have any common factors?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yep lol >.< i think urghh i should of paid attention :P and i just didnt know how to write it bc of the  and + signs >.< lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well they don't have a common factor, and because of that the LCM of them is their multiplication.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ahhhhhh alright i get it so far. ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so (m+2)(m2)=m^24. That's would be our LCM.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That's good. Now, we have to apply this to our equation.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohhhh haha wow ya bc since they dont have a common factors u'd multiply them together. alright.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That means, we will multiply the first term (top and bottom) by (m2). and multiply the second term (top and bottom by (m+2).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Does that make sense?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes so far so good so then the answer would be the "ya" one? lol like my labels? :D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[{4 \over m+2}+{2 \over m2}={4(m2) \over m^24}+{2(m+2) \over m^24}={4m8+2m+4 \over m^24}={6m4 \over m^24}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OR as in the choices: \[{6m4 \over (m+2)(m2)}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0WOOOOOOOOOOOOO!!!! so i was rite huh?!?! YAY YAY YAY!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Haha Yeah you were :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0:) Thanks, helped my bunches! :D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh! and do you think you could help me on part of this other question? :) plesss? lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This is it. do u think u will help meh? :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so ok is the original expression?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You make strange names? :P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0My question is about the denominators again so would there be common factors? >.< i got confused again :P lol and ya i am making strange names ^^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The same first question again, do they have common factors?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0And yea this is the original expression .. pretty sure lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and i thought they did >.< like since 3x can go into 6x.. but then i got lost arghh

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Okay can you factor any of the two denominators?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Wait which version of factoring? >.<

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.03x+5 can't be factored.. (6x+10)=2(3x+5).. right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Okay now your LCD should be each one of the factor to be taken only one. the factors we have are (3x+5) and 2. so our LCD would 2(3x+5).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't think that was clear enough, was it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Not really im sitting here repeating it over in my head going wth.... ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well, you can see that (3x+5) occur in both denominators. right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[{2 \over 3x+5}{1 \over 6x+10}={2 \over 3x+5}{1 \over 2(3x+10)}\] Right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now list all factors in both denominators.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ahhhh so then i see why you would do that. But couldnt you just multiply the 3x + 5 expression by 2 and then subtract?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the two equations with the same denominator i mean ^^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes you could, but then you have to simplify after that.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that wouldn't be the simplest form.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ahhh rite, ^_^ ok then go on lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well you're saying that you multiply the (3x+5) by 2, that's right. And that's what I was trying to say when I said that 2(3x+5) is the LCD. So then we keep the 6x+10 and multiply the (3x+5) term (top and bottom) by 2.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohh so the answer would be B haha wow i rly need to stop doubting myself argh :P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0LOL thanks for the help! AGAIN ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0But you know why we can do that. That's because the denominator of the second term is nothing but 2 times the denominator of the first term.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0AnwarA, how did you make the rational expression look like that ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It's 2(3x+5).. just typo :P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0all I can do is\[{a+bi}/{10ac}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how did you make it go under a long bar ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol think person means like how do u ya long bar ^^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh.. {a+bi over 10a=c}

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0>.< i will never understand computer tech/ math peoples smartness :P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0haha. I think I am the only one who does it this way :P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt(b^24ac) \over 2a\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that is sooo cooooool !! I am goint to use it from now on, thanks!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0LOL obviously not anymore!! :D and i see someone ik viewing the question but he isnt in our meeting place!! >:P lol (inside joke cant rly explain it ^^)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[{\sqrt{b^24ac} \over 2a} \] :P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you do "plus or minus" as well ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0>.< smart people arg lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[{b \pm \sqrt{b^24ac} \over 2a}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how did you make the sqrt top part long ?! I have so much to learn lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Haha try that yourself :P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is there a place that have all of that written down ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0*sigh* so much to learn to little time lmao im jk :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just use {}, with anything that you want to make long :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Hah, i think its funnay how i have no idea how the heck u guys are doing that ^^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[e^{ANWAR}={1 \over \sqrt{yuki}^{dolly}}\] :P that does not mean anything by the way

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits _{a,b}_{b,a}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol im above yuki hee hee!!!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I am in the top, that's what matters :D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0:P looks more like im the glue that holds everything together mwuahahaha!!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0take ln of both sides to bring me down :(

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\cos(a \pm b) = \cos(a)\cos(b) \mp \sin(a)\sin(b)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0But you can't use your weird names there :P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yuki, whenever you use these things, rmr to thank me first

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0awww yep sure the person i am waiting for isnt talking so sure :) lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{a,b \int\limits_{1}^{2}}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0whom are you waiting for? xD

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I definitely will AnwarA

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0his name starts with an I and he is rlyyyy sweet and hot and all tht jaz oh and did i mention it was u ? xD lmao

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0haha anwar is all like wat the hell.... LOL

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thanks buddy!! I was just kidding. I did nothing, anyone who knows that would help do that. :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[{a+bi \over abi} *{a+bi \over abi}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0why do you think I was "all like what the hell"? :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0haha to what i said lol jeezus anwar pay attention!! >:D im jk :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Haha, I read that and I wasn't "all like what the hell" at all :P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yuki, what grade are you at?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0LOL then i was wrong i thought u would be ^_^ lol and prolly college or high school senior!! lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think wherever I need info about anyone in this site, I should just come straight to you. You got it all :O

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do you work for the CIA?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0haha its easy i just notice the kind of math they know how to do, the way they type.. etc :) nm too it :D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so you are not here to gather informations about us for some agencies?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Uhh, no. lol That would only be extremely creepy lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0:) Anyway, I am off to bed. Yuki would be more of help than I am, specially that he now knows how to do the equations thing :D.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0LOL okie dokie nite buddaaayyyy!!! :)
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