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Which one is the question?

the one that says "ok" ^_^

I see.

The process is confusing me im pretty sure this is one of the lessons that i missed :P

So the question is to simplify:
\[{4 \over m+2}+{2 \over m-2}?\]

The m + 2 and m - 2 is confusing me :P And it says to Add and Simplify.

Good. First, what is the LCM of (m+2) and (m-2).

Thats the part that was confusing me ^_^ lol

Haha I see. Do (m+2) and (m-2) have any common factors?

Well they don't have a common factor, and because of that the LCM of them is their multiplication.

Ahhhhhh alright i get it so far. ^_^

so (m+2)(m-2)=m^2-4. That's would be our LCM.

That's good. Now, we have to apply this to our equation.

expression*

ohhhh haha wow ya bc since they dont have a common factors u'd multiply them together. alright.

Exactly.

Does that make sense?

Yes so far so good so then the answer would be the "ya" one? lol like my labels? :D

>.< i think... :P

OR as in the choices:
\[{6m-4 \over (m+2)(m-2)}\]

WOOOOOOOOOOOOO!!!! so i was rite huh?!?! YAY YAY YAY!!

lol ^_^

Haha Yeah you were :)

:) Thanks, helped my bunches! :D

np

Oh! and do you think you could help me on part of this other question? :) plesss? lol

so ok is the original expression?

You make strange names? :P

The same first question again, do they have common factors?

And yea this is the original expression .. pretty sure lol

and i thought they did >.< like since 3x can go into 6x.. but then i got lost arghh

Okay can you factor any of the two denominators?

No i dont think so

Wait which version of factoring? >.<

3x+5 can't be factored..
(6x+10)=2(3x+5).. right?

Right.

I don't think that was clear enough, was it?

Not really im sitting here repeating it over in my head going wth.... ^_^

LOL

Well, you can see that (3x+5) occur in both denominators. right?

after factorization*

Yep i see that.

\[{2 \over 3x+5}-{1 \over 6x+10}={2 \over 3x+5}-{1 \over 2(3x+10)}\] Right?

Now list all factors in both denominators.

I mean 2(3x+5) :)

the two equations with the same denominator i mean ^^

Yes you could, but then you have to simplify after that.

that wouldn't be the simplest form.

Ahhh rite, ^_^ ok then go on lol

:)

ohh so the answer would be B haha wow i rly need to stop doubting myself argh :P

LOL thanks for the help! AGAIN ^_^

AnwarA, how did you make the rational expression look like that ?

It's 2(3x+5).. just typo :P

all I can do is\[{a+bi}/{10a-c}\]

how did you make it go under a long bar ?

lol think person means like how do u ya long bar ^^

Oh.. {a+bi over 10a=c}

And hello yuki.

:)

>.< i will never understand computer tech/ math peoples smartness :P

haha. I think I am the only one who does it this way :P

\[\sqrt(b^2-4ac) \over 2a\]

that is sooo cooooool !! I am goint to use it from now on, thanks!

\[{\sqrt{b^2-4ac} \over 2a} \]
:P

can you do "plus or minus" as well ?

Haha

>.< smart people arg lol

Yep anything

\[{-b \pm \sqrt{b^2-4ac} \over 2a}\]

how did you make the sqrt top part long ?!
I have so much to learn lol

Haha try that yourself :P

is there a place that have all of that written down ?

*sigh* so much to learn to little time lmao im jk :)

just use {}, with anything that you want to make long :)

\[\sqrt{10x+b}\]

Hah, i think its funnay how i have no idea how the heck u guys are doing that ^^

\[e^{ANWAR}={1 \over \sqrt{yuki}^{dolly}}\] :P that does not mean anything by the way

\[\int\limits _{a,b}_{b,a}\]

lol im above yuki hee hee!!!!

I am in the top, that's what matters :D

\[\ln(\ln (x)) = 0\]

:P looks more like im the glue that holds everything together mwuahahaha!!!

take ln of both sides to bring me down :(

\[+,- \pm \]

Ha ! found it lo

You're learning :P

\[\cos(a \pm b) = \cos(a)\cos(b) \mp \sin(a)\sin(b)\]

im not ^_^ LOL

You want to?

But you can't use your weird names there :P

yuki, whenever you use these things, rmr to thank me first

awww yep sure the person i am waiting for isnt talking so sure :) lol

\[\int\limits_{a,b \int\limits_{1}^{2}}\]

Haha

whom are you waiting for? xD

I definitely will AnwarA

haha anwar is all like wat the hell.... LOL

Thanks buddy!! I was just kidding. I did nothing, anyone who knows that would help do that. :)

\[{a+bi \over a-bi} *{a+bi \over a-bi}\]

^_^

why do you think I was "all like what the hell"? :)

haha to what i said lol jeezus anwar pay attention!! >:D im jk :)

Haha, I read that and I wasn't "all like what the hell" at all :P

yuki, what grade are you at?

LOL then i was wrong i thought u would be ^_^ lol and prolly college or high school senior!! lol

Do you work for the CIA?

so you are not here to gather informations about us for some agencies?

Uhh, no. lol That would only be extremely creepy lol

Bye all!!

LOL okie dokie nite buddaaayyyy!!! :)

sigma