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To solve it, you must get everything to one side so the equation equals zero. 6b^2 - 5b - 4 = 0 Then factor it.
Do you know how to factor that?
no thats as far as ive gotten
is the 6b^2-5b-4=0
Do you know if you use trial and error, bottoms up, or what method you usually use?
Foil would be to check it
Factoring is taking it apart. We'll use trial and error. Multiply the first and last numbers and you get -24
What multiplies to be -24 and adds to be -5 (the middle term)
3 and 8
Yeah, 3 and -8. So you know your "inner" and outter terms have to equal 3 and
6 factors to be 2 * 3 or 1 * 6 and 4 can be 2 * 2 or 4 *1
You know you have to have "3" for one of your numbers, so you know it's set up like this.... (3x + ____) (2x + ____)
Since you know you need a 3. that last blank must be a positive 1. (3x + ___)(2x + 1) . That makes your outter terms equal 3.
Therefore your inner terms must equal -8. So what would need to go in that blank?
Yup. So that gives you (3x - 4)(2x + 1) Then to check it, just FOIL it back together.
wait shouldnt the answer come out to be x= and then like 2 fractions cause on the last one that i did that asked for the equation to be solved and check solution it came out to be n=-1/3 and 2/5
Yes, just set each ( ) equal to zero and solve. The answers should be x = 4/3 and x = -1/2