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anonymous

  • 5 years ago

A cylinder tank with already 1 inch deep has a radius of 5 feet and a heigh of 10 feet. Water runs into the tank at the constant rate of 2 cu ft /min. How fast is the water level is rising when the water is 6 ft deep. WE know V=Pi*r^2 h. Which of the following is true? A. dr/dt=0 and we solve for dh/dt B. dr/dt=0 and we solve for dV/dt C. There is not enough info, we need dr/dt D. Not enough info, we need dV/dt

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  1. anonymous
    • 5 years ago
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    A.

  2. anonymous
    • 5 years ago
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    can you explain?

  3. anonymous
    • 5 years ago
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    I don't like any of the answers but I would choose A as well. The radius is not changing, so there is no rate of change for it. Hence dr/dt = 0.

  4. anonymous
    • 5 years ago
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    You are looking for how fast the water level is rising (that's height) so you are looking for dh/dt

  5. anonymous
    • 5 years ago
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    There is enough info to solve the problem so it couldn't be C. or D. and you're not looking for dV/dt. So that only leaves A :)

  6. anonymous
    • 5 years ago
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    yes, as math93 said. The radius in a cylinder is constant. so it does not change over time. therefore dr/dt = 0. You are interested in finding out how height changes over time, specifically when h = 6. so you find out dh/dt and find out its value at h =6

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