[[HARD - Polynomials]] Consider the curve y = x^5 - 10x^4 + 22x^3 + 32x^2 - 20x + 20. Find the equation of the line which intersects the curve at (-2, -180) and is a tangent to the curve at two other points.

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[[HARD - Polynomials]] Consider the curve y = x^5 - 10x^4 + 22x^3 + 32x^2 - 20x + 20. Find the equation of the line which intersects the curve at (-2, -180) and is a tangent to the curve at two other points.

Mathematics
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Modulas can u help me after her
please
Take derivative, find zeros, then find the points of those zeros in the original equation. When you have the points (there shouldn't be too many) find which 2 make a line that intersects the given point.

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or actually nm, those zeros wont work because the slope of the line you need isn't going to be 0
mm. I differentiated y, but I don't know what to do with the differential. I let the line be y = mx + b and set x^5 - 10x^4 + 22x^3 + 32x^2 - 20x + 20 = mx + b Kindda stuck after that
You need a slope around x = 5 and .5 that is the same. But how to get that I'm not sure.
and if that is the derivative, the derivative should = m since it will serve as the slope
I gtg though, gl with it
alright, thanks.

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