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anonymous

  • 5 years ago

12x^2-1=-x solve the equationa dn check your solution

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  1. anonymous
    • 5 years ago
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    first put it in the standard form ax^2+bx+c =0 and post it here

  2. anonymous
    • 5 years ago
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    ??

  3. anonymous
    • 5 years ago
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    add x to both sides of the equation and post what you get.

  4. anonymous
    • 5 years ago
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    i dont get what you mean so yeahhh

  5. anonymous
    • 5 years ago
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    have you done algebra before?

  6. anonymous
    • 5 years ago
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    no

  7. anonymous
    • 5 years ago
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    lol then how come you have to do these questions?

  8. anonymous
    • 5 years ago
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    oh. okay. Then you really shouldn't be doing this sort of problem. Let me post a couple of links so that you can first learn some basic algebra and then come back here.

  9. anonymous
    • 5 years ago
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    this is my first year doing algebra and i have a 27% and have to retake it next yuear

  10. anonymous
    • 5 years ago
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    oh. You really should learn how to do these questions. They're not hard ^^ Here's your answer with explanations: 12x² - 1 = -x [[move everything to one side and get the equation into the general form ax²+bx+c =0]] 12x² + x - 1 = 0 [[You're looking for 2 numbers, m and n, with the conditions that m+n = b and mn = ac. So in this case, two numbers that add to be 1 and multiply to be -12. 4 and -3 work, so split x into 4x and -3x]] 12x² + 4x - 3x - 1 = 0 [[Factorize by grouping in pairs]] 4x(3x + 1) - (3x + 1) = 0 [[Factorise (3x+1) out]] (4x - 1)(3x + 1) = 0 [[Solve]] x = 1/4 or x = -1/3

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spraguer (Moderator)
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