• anonymous
A voltage source e(t), which has a value of 2V at t=0, rises exponentially to a final value of 6V with a time constant of 3sec. Determine the expression for e(t). I have possible answers a) e(t)=(6-4e^(-t/3))u(t) b) e(t)=6e^(-t/3)u(t) c)e(t)=(2+4e^(-t/3))u(t) d)e(t)(6-2e^(-3t))u(t)
Mathematics
• Stacey Warren - Expert brainly.com
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SOLVED
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