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anonymous
 5 years ago
I need help in my algebra its pretty simple but i am not sure on my answer :)
anonymous
 5 years ago
I need help in my algebra its pretty simple but i am not sure on my answer :)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the one labeled shape is the problem ^^ :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0To find the perimeter, add up all the sides. (5x/6) + (x/3) + (x/3) + (x/3) (5x/6) + 3(x/3) (5x/6) + x (5x/6)+(6x/6) 11x/6

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ahhhhhh alright i was right about the answer then :) idk the process confuzzles me ^^ idk why lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.03/ (x5) + 5/ (x^225) ** (x^225) can be written as (x5)(x+5) So therefore: 3/ (x5) + 5/ (x5)(x+5) Find LCD (least common denominator) (3(x+5) + 5)/ (x5)(x+5) (3x+15+5)/ (x5)(x+5) (3x+20)/ (x5)(x+5)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ahhh alright im pretty sure that there is more but i am going to have to firgure that on my own but thanks a bunch!! :D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0btw u should be a frickin teacher! xD

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0:P one more but i dont have to attach it lol ur steps are frickin daving my life!! :D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(x2 + 10x + 9) and (x2  1) A. (x + 1) B. (x + 1)( x + 9) C. (x + 1)(x  1) D. (x + 1)(x  1)(x + 9)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Which of the following is the LCM of the polynomials?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think i get confused with GCF and LCM :P i dont even remember wht each means!?!? :P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0For (x2 + 10x + 9), Multiples are (x+9), (x+1) For (x21) Multiples are (x1), (x+1) LCM is Least Common Multiple... So the least common multiple for both is (x+1), which is A

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ahhhhh, i see why that would be the answer then!! :)
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