anonymous
  • anonymous
3 Parts to this question a. Find the value of the discriminant b. Give the nukber of real solutions c. Find the real solutions, rounded to the nearest hundred. r^(2) + 6r + 4 = 0 (this is a reallu weird question so if you dont understand it i understand)
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
The discriminant = \[b ^{2}-4ac = 6^{2}-4*1*4 = 36 - 32 = 4\] # of Real Solutions: 2 Real solutions using quadratic formula (check my algebra carefully cause I tend to get sloppy): \[(-b \pm \sqrt{b ^{2}-4ac})/2a\] \[(-(-6) \pm \sqrt{6^{2}-4*1*4)}/2*1\] = \[6 \pm \sqrt{36-32}/2=6 \pm \sqrt {4}/2 = 3 \pm 1 = 4,2\]
anonymous
  • anonymous
And check my work via FOIL or whatever method you prefer.
anonymous
  • anonymous
Oh, and something is wrong since 4*2 does not equal 4.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
im confused how did ur 6 become -(-6) when it was positive to begin with shouldnt it have become -(6) and htere for -6 + or - not 6 + or -?
anonymous
  • anonymous
Yep.
anonymous
  • anonymous
Like I said I get sloppy with my algebra and arithmetic. Sorry. I think something is still wrong in there somewhere but I'm going to be lazy with it.
anonymous
  • anonymous
atleast it was caught XD

Looking for something else?

Not the answer you are looking for? Search for more explanations.