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anonymous
 5 years ago
solve the following using augmented matrix's
4x7y=2
x+2y=7
(pls show work so i can understand thx)
anonymous
 5 years ago
solve the following using augmented matrix's 4x7y=2 x+2y=7 (pls show work so i can understand thx)

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1[4 7  2] [1 2  7]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1matrix is just the elimination process without the variables getting in the way

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1[4 7  2] [1 2  7] < (*4) [ 4 7   2] [4 8  28] < (subtract R2 from R1) [ 4 7   2] [4 8  28]  [0 15  30] < (/15) to get the 2nd number to be a 1 [0 1  2] < new R2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1[ 4 7  2] < (/4) to get teh 1st number to be 1 [0 1  2] [1 7/4  1/2] [0 1  2 ] <(*7/4) and subtract from R1

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1[1 7/4  1/2] [0 7/4  7/2 ]  [1 0  6/2] < new R1, reduce 6/2 to 3 [1 0  3] [0 1  2]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1with any luck; x=3 and y = 2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.14(3)7(2)=2 12  14 = 2 checks (3)+2(2)=7 3 + 4 = 7 checks

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1it is the same process as elimination; since the variables dont matter anyways; we can just strip them out of the way and work with the numbers instead

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dear god thank you tho i still dnt quite understand how to do the other 4 :(

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1instead of trying to hunt down the [,, and ] buttons im gonna leave them out ot it ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0alrighty thanks want me to post here or under ask a question?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0btw you are saying my graduation i have all the other parts of my precal credit recovery but this haha i wish i could thank you in person my teachers at school scratched their heads and said good luck thank you

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.011. 5x=3y50 2y=13x 13. x+y+z=2 2x3y+z=11 x+2yz=8

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1do you know how to solve a system of equations by elimination?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if i saw the problem i could tell you but i dnt remember alot of precal vocab

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.15 3 = 50 ; Row1(R1) should be gotten to a 1 0 format 3 2 = 1 ; Row2(R2) should be gotten to a 0 1 format here

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.15 3 = 50 ; if we /5 we get a 1 x = x right? 3 2 = 1 1 3/5 = 10 ; *3 to eliminate the 3 in R2 3 2 = 1 3 9/5 = 30 3 2 = 1 < add them together  0 1/5 = 29 < *5 to turn that 1/5 unto a 1 0 1 = 145 < this tells us y = 145 if i did it right lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the ansers shld come out to be x= 97/19 and y= 155/19 in the back of the book

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.11 3/5 = 10 ; new R1 0 1 = 145 ; new R2 < (*3/5) to eliminate the 3/5 in R1 1 3/5 = 10 0 3/5 = 87 < add them toghter  1 0 = 97 but i could have typos somewhere :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1let me recheck without the explanations ok....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.15x 3y=50 3x+2y = 1 < had a 3 there...bad me lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.15 3 = 50 (/5) 3 +2 = 1 1 3/5 = 10 ; *3 3 +2 = 1 3 + 9/5 = +30 3 +10/5 = 1  0 19/5 = 31 (5/19) 0 1 = 151/19 ??

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.131 5  155 lol 155/19

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.11 3/5 = 10 0 1 = 155/19 (3/5) 1 3/5 = 10 0 3/5 = 93/19  1 0 = 190+93/19 190 93  97/19 1 0 = 97/19 0 1 = 155/19 right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1its easier on the paper lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1does it look any easier yet :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0starting to but i look at these problems and i just feel myself getting lost :(

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.11 1 1 =  2 2 3 1 = 11 1 2 1 = 8

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1when we look at this the 1st and 3rd are ready to be added togeter and eliminate that 1 right

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh the first and third 1 tho

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dnt we need the bottom right to be 1?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i guess we do that later?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.11 1 1 =  2 1 2 1 = 8  0 3 0 = 6 (/3) 0 1 0 = 2 ..... y = 2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1we use R1 to calibrate R2 and R3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but hte third row is z?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so dnst it also need it to be 0 0 1?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.11 1 1 =  2 (*2) 2 3 1 = 11 2 2 2= 4 2 3 1 = 11  0 5 1 = 7 < new R3

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1we dont have to keep the rows in order; just as long as we pick an order and stick to it :) to keep things organized for us lol it just so happened that R3 made a perfect R2 :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.10 1 0 = 2 (*5) 0 5 1 = 7 0 5 0 = 10 0 5 1 = 7  0 0 1 = 3 (*1) 0 0 1= 3 z=3

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.11 1 1 =  2 0 1 0 = 2 0 0 1 = 3 1 2 3 = 2 1 0 0 = 2 2 3 1 0 0 = 1 x = 1 right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait when did R1 become 1 2 3 ?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.11 0 0 = 1 0 1 0 = 2 0 0 1 = 3 1 1 1 = 2 : mean x+y+z = 2 x +2  3 = 2 x = 22+3 x = 1

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1whenever we know what a '1' in a column equals; we can substitute it to find aonther :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0see i didnt think you could so yet another reason why i couldnt self teach myself this hey do you want to keep going or food break?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1lol..... how many more you got? just remember that we stripped the variables and that a 1 = the variable 0 1 0 = 2 means!! 1y=2, y=2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0two more of this type and 1 more then IM DONE HURRAY and ya that makes sense just couldnt wrape my head around the concept im working 6 hours math after school with about four to three hours of sleep a night its catching up too me :(

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1x y z = #  1 0 0 = 1 0 1 0 = 2 0 0 1 = 3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i dont even get the option of failing this cause my navy nuke recruiter wld kill me :(

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1lol.... i dont know much about matrixes, but i do know this :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1linear algebra has lots of matrix stuff in it :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1and maybe discrete mathematics

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1post a new question box so we dont bog this post down ...long posts tend to slow my system ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0k ill throw up the last two of these and grab a snack and brb here they are
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