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anonymous
 5 years ago
1X^(2) + 28  48 = 0
anonymous
 5 years ago
1X^(2) + 28  48 = 0

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.01x^220=0 X^2=20 x=square root of 20 though i dont know if your question accepts decimals or not

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if the question is actually \[x ^{2} + 2x  48\] You need factors that when added equal 2 and when multiplied equal 48 factors of 48: 1x48 2x24 4x12 6x8 Will any of those work?

gw2011
 5 years ago
Best ResponseYou've already chosen the best response.0If the problem is x^2+28x48, then there are no factors of 48 that will give the middle term of +28x. So, you need to use the Quadratic Formula to solve this problem. The Quadratic Formula is: x = [b plus or minus (square root of b^2  4 (a)(c))]/2a Then: a=1 b=28 c=48 x = [28 plus or minus (square root of (28)^2  4(1)(48))]/2(1) = [28 plus or minus (square root of 784 + 192)]/2 = [28 plus or minus (square root of 976)]/2 = [28 plus or minus (square roots of (16)(61))/2 = [28 plus or minus 4(square root 61)]/2 x = 14+2(square root 61) and x = 142(square root 61)
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