anonymous
  • anonymous
625x^4 - 64y^8
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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yuki
  • yuki
the hint to this problem is that these two terms are suspiciously using perfect squares,
yuki
  • yuki
so you use the idea of "difference of squares" \[(a+b)(a-b) = a^2 -b^2\]
yuki
  • yuki
\[625x^4 = (25x)^2\] and \[64y^4 = (8y^4)^2\]

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yuki
  • yuki
so you can factor this as \[(25x^2-8y^4)(25x^2+8y^4)\]
yuki
  • yuki
the left part of the factors are again, difference of squares, so you can use the idea again to get something the only thing here is that 8 is not a perfect square anymore, so you can either leave it like this or factor even further like \[(5x-2\sqrt{2}y^2)(5x+2\sqrt{2}y^2)\]
yuki
  • yuki
are you good ?
anonymous
  • anonymous
yes! thank you so mich

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