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anonymous

  • 5 years ago

625x^4 - 64y^8

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  1. Yuki
    • 5 years ago
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    the hint to this problem is that these two terms are suspiciously using perfect squares,

  2. Yuki
    • 5 years ago
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    so you use the idea of "difference of squares" \[(a+b)(a-b) = a^2 -b^2\]

  3. Yuki
    • 5 years ago
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    \[625x^4 = (25x)^2\] and \[64y^4 = (8y^4)^2\]

  4. Yuki
    • 5 years ago
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    so you can factor this as \[(25x^2-8y^4)(25x^2+8y^4)\]

  5. Yuki
    • 5 years ago
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    the left part of the factors are again, difference of squares, so you can use the idea again to get something the only thing here is that 8 is not a perfect square anymore, so you can either leave it like this or factor even further like \[(5x-2\sqrt{2}y^2)(5x+2\sqrt{2}y^2)\]

  6. Yuki
    • 5 years ago
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    are you good ?

  7. anonymous
    • 5 years ago
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    yes! thank you so mich

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