anonymous 5 years ago 625x^4 - 64y^8

1. anonymous

the hint to this problem is that these two terms are suspiciously using perfect squares,

2. anonymous

so you use the idea of "difference of squares" $(a+b)(a-b) = a^2 -b^2$

3. anonymous

$625x^4 = (25x)^2$ and $64y^4 = (8y^4)^2$

4. anonymous

so you can factor this as $(25x^2-8y^4)(25x^2+8y^4)$

5. anonymous

the left part of the factors are again, difference of squares, so you can use the idea again to get something the only thing here is that 8 is not a perfect square anymore, so you can either leave it like this or factor even further like $(5x-2\sqrt{2}y^2)(5x+2\sqrt{2}y^2)$

6. anonymous

are you good ?

7. anonymous

yes! thank you so mich