anonymous
  • anonymous
Does anybody know how to solve rational equations with polynomial denominators?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
if so comment and i will post the question ^^
yuki
  • yuki
I do
yuki
  • yuki
I helped someone with that so I will guid you there

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anonymous
  • anonymous
Alrighty thx!! :) the problem is: x = 1 +1 2x+4 x+2
anonymous
  • anonymous
i dont know how to do the lines underneath ^^
yuki
  • yuki
it's in clark's problem the idea is there, so if you want to know the steps they are all there
anonymous
  • anonymous
Alrighty!!! can u link me maybe?
yuki
  • yuki
actually, yours is an equation. not an inequality, so nvm
yuki
  • yuki
uh... I just noticed this but what did I do ? lol there are so many postings... creepy
anonymous
  • anonymous
Wow!! that looks like exactely what i need!!! :D thanks a bunch!!! :) Totally giving u medals lol :)
yuki
  • yuki
wait up 1<3, yours is different and much easier so stay here and listen
anonymous
  • anonymous
alright im listening!! :)
yuki
  • yuki
\[{x \over 2x +4 } = {1 \over x+2 } +1 \]
yuki
  • yuki
right ?
anonymous
  • anonymous
You can also watch Sal on khanacademy: http://www.khanacademy.org/v/solving-rational-equations-1?p=Algebra%20I%20Worked%20Examples
anonymous
  • anonymous
Alright u guys have helped me massively!! :) Now i gtg and do more work :P might not be on later depends on if i need help or not or if i have time ^_^ lol
yuki
  • yuki
the first thing you want to do here is to find out the common denominator for all terms you have,
anonymous
  • anonymous
gl!
anonymous
  • anonymous
Thanks :)
yuki
  • yuki
I'll leave the steps so that you can look at it later ok ?
anonymous
  • anonymous
Ahww thank you that is extremely helpful of u =3
anonymous
  • anonymous
cuz i k i will definitely look at the steps ^_^
yuki
  • yuki
the LCD is 2x+4, so if you multiply that on both sides you will get \[x = 2 + 2x+4\]
yuki
  • yuki
if you solve that x = -6
yuki
  • yuki
the only thing you have to be careful is to make sure that when you start the problem, you identify the "extraneous solutions' basically the x's that makes any denominator in our eqn =0 since x = -2 is such number, it will never be the answer
yuki
  • yuki
since we did not deduce that x = -2, we just ignore it, but if x =-2 was what we deduced, then there is no solution. okay, hope you do well.
anonymous
  • anonymous
Thanks a BUNCH!!!! ur steps totally helped me :)

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