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anonymous

  • 5 years ago

15. x+y+z-6=0 2x-3y+4z-3=0 4x-8y+4z-12=0 17.w+x+y+z=0 2w+x-y-z=1 -w-x+y+z=o 2x+y=o

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  1. amistre64
    • 5 years ago
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    1 1 1 = 6 2 -3 4 = 3 4 -8 4 = 12 1 1 1 = 6 (-2) -2 -2 -2 =-12 2 -3 4 = 3 2 -3 4 = 3 ------------- 0 -5 2 = -9 .......................................................... 1 1 1 = 6 (*-4) -4 -4 -4 = -24 4 -8 4 = 12 4 -8 4 = 12 -------------- 0 -12 0 = -12 (/-12) 0 1 0 = 1 ......................................................... 0 -5 2 = -9 0 -5 2 = -9 0 1 0 = 1 (5) 0 5 0 = 5 -------------- 0 0 2 = -4 (/2) 0 0 1 = -2

  2. amistre64
    • 5 years ago
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    1 1 1 = 6 0 1 0 = 1 0 0 1 = -2 1 1 -2 = 6 1 0 0 = 6-1+2 x y z =# --------- 1 0 0 = 7 0 1 0 = 1 0 0 1 = -2

  3. amistre64
    • 5 years ago
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    1 1 1 1 = 0 2 1 -1 -1 = 1 -1 -1 1 1 = 0 2 1 0 0 = 0 1 1 1 1 = 0 -1 -1 1 1 = 0 (add em up, they are good to go) --------------- 0 0 2 2 = 0 .............................................................. 1 1 1 1 = 0 (*-2) -2 -2 -2 -2 = 0 2 1 -1 -1 = 1 2 1 -1 -1 = 1 --------------- 0 -1 0 -3 = 1 .................................................................. 1 1 1 1 = 0 (*-2) -2 -2 -2 -2 = 0 2 1 0 0 = 0 2 1 0 0 = 0 --------------- 0 -1 -2 -2 = 0 ............................................................... 1 1 1 1 = 0 0 -1 0 -3 = 1 (*-1) 0 1 0 3 = -1 0 -1 0 -3 = 1 0 -1 -2 -2 = 0 ............................................................... 0 1 0 3 = -1 0 -1 0 -3 = 1 -------------- 0 0 0 0 = 0 this is a sign for infinity solutions ........................................... 0 1 0 3 = -1 0 -1 -2 -2 = 0 ----------------- 0 0 -2 1 = -1

  4. amistre64
    • 5 years ago
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    1 1 1 1 = 0 0 1 0 3 = -1 0 0 -2 1 = -1 (/-2) 0 0 1 -1/2 = 1/2 0 0 0 0 = 0 ................................................ 1 1 1 1 = 0 0 1 0 3 = -1 0 0 1 -1/2 = 1/2 0 0 0 0 = 0

  5. amistre64
    • 5 years ago
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    w+x+y+z=0 2w+x-y-z=1 -w-x+y+z=0 y = -2x ------------------- w-x+z=0 w = x-z 2(x-z)+3x-z=1 -- 2x-2z+3x-z = 1 -(x-z)-3x+z=0 -- -x +z -3x+z = 0 ..................................... 5x -3z = 1 -4x +2z = 0 -- z = 2x 5x -2x = 1 3x = 1 x = 1/3 z = 2(1/3) = 2/3 w = x-z = 1/3 - 2/3 = -1/3 y = -2x = -2(1/3) = -2/3

  6. amistre64
    • 5 years ago
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    i see the typo in my matrix that goofed me up lol.... -2 -2 -2 -2 = 0 2 1 -1 -1 = 1 --------------- 0 -1 -3 -2 = 1 ^^ i made that a '0' last time :)

  7. anonymous
    • 5 years ago
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    was about to say the book says answer is 1, -1, 2, -2

  8. anonymous
    • 5 years ago
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    shld i erase up to the mistake?

  9. amistre64
    • 5 years ago
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    you could erase it up to that point :)

  10. anonymous
    • 5 years ago
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    got it to 1 0 0 0 1 0 1 00 -1 0 0 1 1 0 0 -1 -2 -2 0

  11. anonymous
    • 5 years ago
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    YES ALL THE STUFF U TAUGHT ME MAKES SENSE HAHAHA YES 1 SEC WANNA SEE IF I CAN GET TO 1 0 0 0 0 1 0 0 0 0 1 0 0 0 0 1 0

  12. anonymous
    • 5 years ago
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    sry caps

  13. amistre64
    • 5 years ago
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    lol....little excited eh :)

  14. anonymous
    • 5 years ago
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    well i was then i forgot wtf went thru my brain can get to 1 0 0 0 1 0 1 0 0 -1 0 0 1 1 0 0 -1 -2 -2 0

  15. anonymous
    • 5 years ago
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    what shld i do now?

  16. amistre64
    • 5 years ago
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    0 0 1 1 = 0 0 -1 -2 -2 = 0 switch these 2 rows 1 0 0 0 = 1 0 1 0 0 = -1 0 -1 -2 -2 = 0 (*1) 0 0 1 1 = 0

  17. amistre64
    • 5 years ago
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    or subtract it from the R2

  18. anonymous
    • 5 years ago
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    oh didnt know i could swap rows

  19. amistre64
    • 5 years ago
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    0 1 0 0 =-1 0-1-2-2= 0 ------------- 0 0 2 2 =-1 (/2) 0 0 1 1 = -1/2 .....maybe?

  20. amistre64
    • 5 years ago
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    matrix can be cumbersome.....

  21. anonymous
    • 5 years ago
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    nah cause the answers are 1, -1 2, -2

  22. anonymous
    • 5 years ago
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    and thats and understatement

  23. amistre64
    • 5 years ago
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    -2 -2 -2 -2 = 0 2 1 -1 -1 = 1 --------------- 0 -1 -3 -3 = 1 (*1) 0 1 3 3 = 1 ..............................

  24. anonymous
    • 5 years ago
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    wait how does that work cause if you times whole line by -1 to make them positives it makes the 1 -1 right?

  25. amistre64
    • 5 years ago
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    1 1 1 1 = 0 0 1 3 3 = 1 0 1 3 3 = 1 0 -1 -2 -2 = 0 0 -1 -2 -2 = 0 0 0 2 2 = 0 -------------- 0 0 -1 -1 =1 (-1) 0 0 1 1 = -1 .......................................................... 0 1 3 3 = 1 0 0 2 2 = 0 ------------- 0 1 5 5 = 1

  26. anonymous
    • 5 years ago
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    wait im confused if ur adding 0 1 3 3 1 to 0 -1 -2 -2 0 wouldnt it be 0 0 1 1 1? then when times by -1 0 0 -1 -1 -1?

  27. amistre64
    • 5 years ago
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    1 1 1 1 = 0 0 1 3 3 = 1 0 0 1 1 = -1 ...cant seem to wrap this up lol

  28. amistre64
    • 5 years ago
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    im gonna write this on paper; its a nightmare trying to keep things sorted in this reply box lol

  29. anonymous
    • 5 years ago
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    OMFG WE FAILED SO HARD AHHAHAHHAHA

  30. anonymous
    • 5 years ago
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    4rth row is not 2 1 0 0 y is third in all the others so wouldnt it be 2 0 1 0

  31. anonymous
    • 5 years ago
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    sry 0 2 1 0

  32. amistre64
    • 5 years ago
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    lol...your right

  33. anonymous
    • 5 years ago
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    always goes w x y z we have x and y

  34. anonymous
    • 5 years ago
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    haha if only i could fit all of this onto failblog or unfreindable

  35. amistre64
    • 5 years ago
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    1 1 1 1 =0 2 1 -1-1 =1 -1 -1 1 1 =0 0 2 1 0 =0 lol yeah :)

  36. anonymous
    • 5 years ago
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    dear god getting a drink and cranking this out hey btw meant to ask you earleir are you a teacher or what do you do?

  37. amistre64
    • 5 years ago
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    im an unemployed carpenter going back to college :)

  38. anonymous
    • 5 years ago
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    well congratz on going back my brother is going back soon too and my other brother is just about to finish at the community but im going into the navy already signed why i have to get this stuff done

  39. amistre64
    • 5 years ago
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    1 1 11=0 -1-111=0 ---------- 0 0 2 2 = 0 -2-2-2-2=0 2 1 -1-1=1 ------------ 0-1-3-3=1 -2-2-2-2=0 0 2 1 0 =0 ------------ -2 0-1-2=0

  40. amistre64
    • 5 years ago
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    1 1 1 1 = 0 0 1 3 3 =-1 0 0 1 1 =0 -2 0-1-2=0

  41. anonymous
    • 5 years ago
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    R1 times 2 add to R4 and swap R4 and R3?

  42. amistre64
    • 5 years ago
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    pawn to queen3 lol

  43. anonymous
    • 5 years ago
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    rofl nvm

  44. amistre64
    • 5 years ago
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    2 2 2 2=0 -20-1-2=0 ----------- 0 2 1 0 = 0 ....cant hurt lol

  45. anonymous
    • 5 years ago
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    oh times R3 by -3 add to R2?

  46. anonymous
    • 5 years ago
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    hahah like an undobutton

  47. amistre64
    • 5 years ago
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    0 1 3 3 =-1 (*-2) 0 2 1 0 = 0 0-2-6-6 =2 0 2 1 0 =0 ----------- 0 0 -5 -6 = 2

  48. amistre64
    • 5 years ago
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    0 0 1 1 =0 (*5) 0 0 -5 -6 = 2 00 5 5=0 00 -5-6 =2 ----------- 0 0 0 -1 = 2 0001=-2

  49. amistre64
    • 5 years ago
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    1 1 1 1 = 0 0 1 3 3 =-1 0 0 1 1 = 0 1 -2 = 0; 1 0=2 0 0 0 1 =-2

  50. amistre64
    • 5 years ago
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    1 1 1 1 = 0 0 1 3 3 =-1 <-- 0 1 6 -6 = -1 ; 0100=-1 0 0 1 0=2 0 0 0 1 =-2

  51. amistre64
    • 5 years ago
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    1 1 1 1 = 0 <- 1 -1 2-2=0; 1000=1 2-2; 1000=1 0 1 0 0 =-1 0 0 1 0 = 2 0 0 0 1 =-2

  52. amistre64
    • 5 years ago
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    1 0 0 0 = 1 0 1 0 0 =-1 0 0 1 0 = 2 0 0 0 1 =-2

  53. amistre64
    • 5 years ago
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    did you get all that lol

  54. anonymous
    • 5 years ago
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    yes thx man for everything is there a way to add you so i cld maybe get future help if need be and ur ok with it?

  55. amistre64
    • 5 years ago
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    add me? not that i know of; just come by and if im here say hi :)

  56. amistre64
    • 5 years ago
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    do i deserve a medal :) lol

  57. anonymous
    • 5 years ago
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    i gave you one long time ago

  58. anonymous
    • 5 years ago
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    oh sweet can give you another

  59. amistre64
    • 5 years ago
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    true ;)

  60. amistre64
    • 5 years ago
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    yay lol..... thanx :)

  61. anonymous
    • 5 years ago
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    nah man thank you for everything i beat my head agianst this and i just couldnt make it come together in a way that made sense you showed me how to do it even tho my PAID teachers cldnt i honestly cld have failed if not for this then there wld be no navy nuclear school or graduation

  62. amistre64
    • 5 years ago
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    good luck :)

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