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anonymous

  • 5 years ago

Hello! Here is my question: I have in space a line AB where A (0,0,0) and B (3,5,10). I have a point C (4,7,9). I need to find on line AB a point D where the line CD intersects AB if this lines are perpendicular to each other. Please show step by step. Thanks.

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  1. anonymous
    • 5 years ago
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    Find vector AB.

  2. amistre64
    • 5 years ago
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    ab = <3,5,10> right?

  3. amistre64
    • 5 years ago
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    you need to determine if the lines even intersect

  4. anonymous
    • 5 years ago
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    Very good. Now call D, xyz and find CD

  5. amistre64
    • 5 years ago
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    <3,5,10> <x, y, z> --------- 3x +5y +10z = 0

  6. amistre64
    • 5 years ago
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    3(x-4t) +5(y-7t) +10(z-9t) = 0 right?

  7. toxicsugar22
    • 5 years ago
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    chaguanas can u help me with a math question

  8. amistre64
    • 5 years ago
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    x = 3t y = 5t z = 10t is the equation of one line in space

  9. toxicsugar22
    • 5 years ago
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    amistre can u help me

  10. amistre64
    • 5 years ago
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    x = x0+4t y = y0+7t z = z0+9t is the other.... i think

  11. amistre64
    • 5 years ago
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    i can look at it, not sure if i can helptho :)

  12. anonymous
    • 5 years ago
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    I do not remember how to find th Perpendicular

  13. anonymous
    • 5 years ago
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    To find perpendicular is to find the normal, cross two vectors.

  14. anonymous
    • 5 years ago
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    Vector U*V=0 right?

  15. anonymous
    • 5 years ago
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    Yes, Amistre, found AB and CD. Actually, you just test them to see if they are perpendicular.

  16. anonymous
    • 5 years ago
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    AB*CD=0

  17. anonymous
    • 5 years ago
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    AB*CD=0

  18. anonymous
    • 5 years ago
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    Yes, if you dot them and get 0, they are perpendicular

  19. anonymous
    • 5 years ago
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    I will try. How do I find the normal, cross two vectors?

  20. anonymous
    • 5 years ago
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    Yes that is how you found the normal. But in this case by the way the question was asked you were led to the answer to your question without having to do that.

  21. anonymous
    • 5 years ago
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    Thanks

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