anonymous
  • anonymous
Hello! Here is my question: I have in space a line AB where A (0,0,0) and B (3,5,10). I have a point C (4,7,9). I need to find on line AB a point D where the line CD intersects AB if this lines are perpendicular to each other. Please show step by step. Thanks.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
Find vector AB.
amistre64
  • amistre64
ab = <3,5,10> right?
amistre64
  • amistre64
you need to determine if the lines even intersect

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More answers

anonymous
  • anonymous
Very good. Now call D, xyz and find CD
amistre64
  • amistre64
<3,5,10> --------- 3x +5y +10z = 0
amistre64
  • amistre64
3(x-4t) +5(y-7t) +10(z-9t) = 0 right?
toxicsugar22
  • toxicsugar22
chaguanas can u help me with a math question
amistre64
  • amistre64
x = 3t y = 5t z = 10t is the equation of one line in space
toxicsugar22
  • toxicsugar22
amistre can u help me
amistre64
  • amistre64
x = x0+4t y = y0+7t z = z0+9t is the other.... i think
amistre64
  • amistre64
i can look at it, not sure if i can helptho :)
anonymous
  • anonymous
I do not remember how to find th Perpendicular
anonymous
  • anonymous
To find perpendicular is to find the normal, cross two vectors.
anonymous
  • anonymous
Vector U*V=0 right?
anonymous
  • anonymous
Yes, Amistre, found AB and CD. Actually, you just test them to see if they are perpendicular.
anonymous
  • anonymous
AB*CD=0
anonymous
  • anonymous
AB*CD=0
anonymous
  • anonymous
Yes, if you dot them and get 0, they are perpendicular
anonymous
  • anonymous
I will try. How do I find the normal, cross two vectors?
anonymous
  • anonymous
Yes that is how you found the normal. But in this case by the way the question was asked you were led to the answer to your question without having to do that.
anonymous
  • anonymous
Thanks

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