5x^2-7x=0

- anonymous

5x^2-7x=0

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- anonymous

we need help badly :/

- anonymous

x=7/5 , 0

- anonymous

how did you get that answer?

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## More answers

- amistre64

we?? need help?

- anonymous

factor out x to get x(5x-7)=0
this means that either x=0 or 5x-7 =0

- amistre64

factor the equation
(x)(5x-7) = 0 we know that anything times 0 = 0 right?

- anonymous

yes

- amistre64

0(5x-7) = 0
(x)(0) = 0 2 options

- amistre64

makes sense?

- amistre64

yall must be typing on Internet explorer :)

- anonymous

a little were confused cause of the squared

- anonymous

5x^2-7x=0
you factor out x. So you get:
x(5x-7)=0.
Then you have two solutions which are:
x=0 and 5x-7=0
you have x=0 solve. now you have to solve the second part which is 5x-7=0, which we get
5x=7..then we divide by 5 to 7 which we end up getting
x=7/5.
so your answers are x=0 and x=7/5

- anonymous

yeah we are but we are trying to do the answer

- amistre64

i had to switch to firefox; less buggy in this site

- anonymous

chrome is best for this site IMO

- anonymous

yayay! thank you! we got the right answer then

- amistre64

yay!!! :)

- anonymous

yay! I share your joy

- anonymous

lol

- amistre64

i tell my kids when they get math wrong. i say, quit breaking the math...when its gone thats it :)

- anonymous

we dont have anyone in out house hold that knows math

- anonymous

am a math major am about to graduate already from college if any help with with basic proof and from calculus four to and down ill be happy to help.

- amistre64

still using an abacus eh :)

- anonymous

can you help us on the next one?

- amistre64

there more?

- anonymous

yes

- amistre64

ok......but they better be easy ;)

- amistre64

gotta let my sister use her facebook ...... ciao :)

- anonymous

5x^2-8x+3=0

- amistre64

x- /5 ; x- /5
5(3) = 15
1,15; 3,5 = 8
x- 3/5 ; x- 5/5
5x-3 ; x-1
x = 1 and x = 3/5

- amistre64

georgia math lol

- amistre64

sister got distracted by a butterfly ...hurry up

- anonymous

i dont get it

- amistre64

dont get what?

- anonymous

5x^2-8x+3=0
first we have to factor the whole problem which we get
(5x-3)(x-1)=0, then we have again two solutions which are
5x-3=0 and x-1=0
now lets solve 5x-3=0.
which we get 5x=3 and then divive 5 to 3 which we get x=3/5
now we solve for x-1=0.
we get x=1.
we are done so out two solutions are
x=3/5 and x=1

- amistre64

my method or the answer?

- anonymous

your method

- amistre64

lol..... if it can factor into integers; my method will get to it everytime :)

- anonymous

LOL THEIR SWARMING THE PRETTY GIRL XD

- amistre64

i use the clues that are given in the equation to narrow my options

- anonymous

3y^2+5y=2

- amistre64

ihave an option; either divide that 5 out to begin with or do it in the end; i choose to wait til the end

- anonymous

newton yuou explain better then my teacher

- amistre64

3y^2 +5y -2 = 0
split it up into its form..... set it up
y y
the last number has a sign that tells yuou to add or subtract... -2 means subtract gonna be a + and a -
y+ y-
gonna need to divide that three but do it at the end...
y+ /3 ; y- /3

- amistre64

multiply 1st and last number to get option for the middle
3(2) = 6....factor the 6
1,6 well, 6-1=5 so thats what are middle number needs to be
y+6/3 ; y-1/3 reduce

- amistre64

y+2 ; y-1/3 we can stop here to get the zeros or continue to the final form...if theres a fraction left over, stick the bottom of it in front like this:
y+2 ; 3y-1
y = -2; y= 1/3

- amistre64

if it dont factor like this; you should either complete the square method; or quadratic formula ..

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