anonymous
  • anonymous
5x^2-7x=0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
we need help badly :/
anonymous
  • anonymous
x=7/5 , 0
anonymous
  • anonymous
how did you get that answer?

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More answers

amistre64
  • amistre64
we?? need help?
anonymous
  • anonymous
factor out x to get x(5x-7)=0 this means that either x=0 or 5x-7 =0
amistre64
  • amistre64
factor the equation (x)(5x-7) = 0 we know that anything times 0 = 0 right?
anonymous
  • anonymous
yes
amistre64
  • amistre64
0(5x-7) = 0 (x)(0) = 0 2 options
amistre64
  • amistre64
makes sense?
amistre64
  • amistre64
yall must be typing on Internet explorer :)
anonymous
  • anonymous
a little were confused cause of the squared
anonymous
  • anonymous
5x^2-7x=0 you factor out x. So you get: x(5x-7)=0. Then you have two solutions which are: x=0 and 5x-7=0 you have x=0 solve. now you have to solve the second part which is 5x-7=0, which we get 5x=7..then we divide by 5 to 7 which we end up getting x=7/5. so your answers are x=0 and x=7/5
anonymous
  • anonymous
yeah we are but we are trying to do the answer
amistre64
  • amistre64
i had to switch to firefox; less buggy in this site
anonymous
  • anonymous
chrome is best for this site IMO
anonymous
  • anonymous
yayay! thank you! we got the right answer then
amistre64
  • amistre64
yay!!! :)
anonymous
  • anonymous
yay! I share your joy
anonymous
  • anonymous
lol
amistre64
  • amistre64
i tell my kids when they get math wrong. i say, quit breaking the math...when its gone thats it :)
anonymous
  • anonymous
we dont have anyone in out house hold that knows math
anonymous
  • anonymous
am a math major am about to graduate already from college if any help with with basic proof and from calculus four to and down ill be happy to help.
amistre64
  • amistre64
still using an abacus eh :)
anonymous
  • anonymous
can you help us on the next one?
amistre64
  • amistre64
there more?
anonymous
  • anonymous
yes
amistre64
  • amistre64
ok......but they better be easy ;)
amistre64
  • amistre64
gotta let my sister use her facebook ...... ciao :)
anonymous
  • anonymous
5x^2-8x+3=0
amistre64
  • amistre64
x- /5 ; x- /5 5(3) = 15 1,15; 3,5 = 8 x- 3/5 ; x- 5/5 5x-3 ; x-1 x = 1 and x = 3/5
amistre64
  • amistre64
georgia math lol
amistre64
  • amistre64
sister got distracted by a butterfly ...hurry up
anonymous
  • anonymous
i dont get it
amistre64
  • amistre64
dont get what?
anonymous
  • anonymous
5x^2-8x+3=0 first we have to factor the whole problem which we get (5x-3)(x-1)=0, then we have again two solutions which are 5x-3=0 and x-1=0 now lets solve 5x-3=0. which we get 5x=3 and then divive 5 to 3 which we get x=3/5 now we solve for x-1=0. we get x=1. we are done so out two solutions are x=3/5 and x=1
amistre64
  • amistre64
my method or the answer?
anonymous
  • anonymous
your method
amistre64
  • amistre64
lol..... if it can factor into integers; my method will get to it everytime :)
anonymous
  • anonymous
LOL THEIR SWARMING THE PRETTY GIRL XD
amistre64
  • amistre64
i use the clues that are given in the equation to narrow my options
anonymous
  • anonymous
3y^2+5y=2
amistre64
  • amistre64
ihave an option; either divide that 5 out to begin with or do it in the end; i choose to wait til the end
anonymous
  • anonymous
newton yuou explain better then my teacher
amistre64
  • amistre64
3y^2 +5y -2 = 0 split it up into its form..... set it up y y the last number has a sign that tells yuou to add or subtract... -2 means subtract gonna be a + and a - y+ y- gonna need to divide that three but do it at the end... y+ /3 ; y- /3
amistre64
  • amistre64
multiply 1st and last number to get option for the middle 3(2) = 6....factor the 6 1,6 well, 6-1=5 so thats what are middle number needs to be y+6/3 ; y-1/3 reduce
amistre64
  • amistre64
y+2 ; y-1/3 we can stop here to get the zeros or continue to the final form...if theres a fraction left over, stick the bottom of it in front like this: y+2 ; 3y-1 y = -2; y= 1/3
amistre64
  • amistre64
if it dont factor like this; you should either complete the square method; or quadratic formula ..

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