5x^2-7x=0

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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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we need help badly :/
x=7/5 , 0
how did you get that answer?

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Other answers:

we?? need help?
factor out x to get x(5x-7)=0 this means that either x=0 or 5x-7 =0
factor the equation (x)(5x-7) = 0 we know that anything times 0 = 0 right?
yes
0(5x-7) = 0 (x)(0) = 0 2 options
makes sense?
yall must be typing on Internet explorer :)
a little were confused cause of the squared
5x^2-7x=0 you factor out x. So you get: x(5x-7)=0. Then you have two solutions which are: x=0 and 5x-7=0 you have x=0 solve. now you have to solve the second part which is 5x-7=0, which we get 5x=7..then we divide by 5 to 7 which we end up getting x=7/5. so your answers are x=0 and x=7/5
yeah we are but we are trying to do the answer
i had to switch to firefox; less buggy in this site
chrome is best for this site IMO
yayay! thank you! we got the right answer then
yay!!! :)
yay! I share your joy
lol
i tell my kids when they get math wrong. i say, quit breaking the math...when its gone thats it :)
we dont have anyone in out house hold that knows math
am a math major am about to graduate already from college if any help with with basic proof and from calculus four to and down ill be happy to help.
still using an abacus eh :)
can you help us on the next one?
there more?
yes
ok......but they better be easy ;)
gotta let my sister use her facebook ...... ciao :)
5x^2-8x+3=0
x- /5 ; x- /5 5(3) = 15 1,15; 3,5 = 8 x- 3/5 ; x- 5/5 5x-3 ; x-1 x = 1 and x = 3/5
georgia math lol
sister got distracted by a butterfly ...hurry up
i dont get it
dont get what?
5x^2-8x+3=0 first we have to factor the whole problem which we get (5x-3)(x-1)=0, then we have again two solutions which are 5x-3=0 and x-1=0 now lets solve 5x-3=0. which we get 5x=3 and then divive 5 to 3 which we get x=3/5 now we solve for x-1=0. we get x=1. we are done so out two solutions are x=3/5 and x=1
my method or the answer?
your method
lol..... if it can factor into integers; my method will get to it everytime :)
LOL THEIR SWARMING THE PRETTY GIRL XD
i use the clues that are given in the equation to narrow my options
3y^2+5y=2
ihave an option; either divide that 5 out to begin with or do it in the end; i choose to wait til the end
newton yuou explain better then my teacher
3y^2 +5y -2 = 0 split it up into its form..... set it up y y the last number has a sign that tells yuou to add or subtract... -2 means subtract gonna be a + and a - y+ y- gonna need to divide that three but do it at the end... y+ /3 ; y- /3
multiply 1st and last number to get option for the middle 3(2) = 6....factor the 6 1,6 well, 6-1=5 so thats what are middle number needs to be y+6/3 ; y-1/3 reduce
y+2 ; y-1/3 we can stop here to get the zeros or continue to the final form...if theres a fraction left over, stick the bottom of it in front like this: y+2 ; 3y-1 y = -2; y= 1/3
if it dont factor like this; you should either complete the square method; or quadratic formula ..

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