## anonymous 5 years ago 5x^2-7x=0

1. anonymous

2. anonymous

x=7/5 , 0

3. anonymous

how did you get that answer?

4. amistre64

we?? need help?

5. anonymous

factor out x to get x(5x-7)=0 this means that either x=0 or 5x-7 =0

6. amistre64

factor the equation (x)(5x-7) = 0 we know that anything times 0 = 0 right?

7. anonymous

yes

8. amistre64

0(5x-7) = 0 (x)(0) = 0 2 options

9. amistre64

makes sense?

10. amistre64

yall must be typing on Internet explorer :)

11. anonymous

a little were confused cause of the squared

12. anonymous

5x^2-7x=0 you factor out x. So you get: x(5x-7)=0. Then you have two solutions which are: x=0 and 5x-7=0 you have x=0 solve. now you have to solve the second part which is 5x-7=0, which we get 5x=7..then we divide by 5 to 7 which we end up getting x=7/5. so your answers are x=0 and x=7/5

13. anonymous

yeah we are but we are trying to do the answer

14. amistre64

i had to switch to firefox; less buggy in this site

15. anonymous

chrome is best for this site IMO

16. anonymous

yayay! thank you! we got the right answer then

17. amistre64

yay!!! :)

18. anonymous

19. anonymous

lol

20. amistre64

i tell my kids when they get math wrong. i say, quit breaking the math...when its gone thats it :)

21. anonymous

we dont have anyone in out house hold that knows math

22. anonymous

am a math major am about to graduate already from college if any help with with basic proof and from calculus four to and down ill be happy to help.

23. amistre64

still using an abacus eh :)

24. anonymous

can you help us on the next one?

25. amistre64

there more?

26. anonymous

yes

27. amistre64

ok......but they better be easy ;)

28. amistre64

gotta let my sister use her facebook ...... ciao :)

29. anonymous

5x^2-8x+3=0

30. amistre64

x- /5 ; x- /5 5(3) = 15 1,15; 3,5 = 8 x- 3/5 ; x- 5/5 5x-3 ; x-1 x = 1 and x = 3/5

31. amistre64

georgia math lol

32. amistre64

sister got distracted by a butterfly ...hurry up

33. anonymous

i dont get it

34. amistre64

dont get what?

35. anonymous

5x^2-8x+3=0 first we have to factor the whole problem which we get (5x-3)(x-1)=0, then we have again two solutions which are 5x-3=0 and x-1=0 now lets solve 5x-3=0. which we get 5x=3 and then divive 5 to 3 which we get x=3/5 now we solve for x-1=0. we get x=1. we are done so out two solutions are x=3/5 and x=1

36. amistre64

37. anonymous

38. amistre64

lol..... if it can factor into integers; my method will get to it everytime :)

39. anonymous

LOL THEIR SWARMING THE PRETTY GIRL XD

40. amistre64

i use the clues that are given in the equation to narrow my options

41. anonymous

3y^2+5y=2

42. amistre64

ihave an option; either divide that 5 out to begin with or do it in the end; i choose to wait til the end

43. anonymous

newton yuou explain better then my teacher

44. amistre64

3y^2 +5y -2 = 0 split it up into its form..... set it up y y the last number has a sign that tells yuou to add or subtract... -2 means subtract gonna be a + and a - y+ y- gonna need to divide that three but do it at the end... y+ /3 ; y- /3

45. amistre64

multiply 1st and last number to get option for the middle 3(2) = 6....factor the 6 1,6 well, 6-1=5 so thats what are middle number needs to be y+6/3 ; y-1/3 reduce

46. amistre64

y+2 ; y-1/3 we can stop here to get the zeros or continue to the final form...if theres a fraction left over, stick the bottom of it in front like this: y+2 ; 3y-1 y = -2; y= 1/3

47. amistre64

if it dont factor like this; you should either complete the square method; or quadratic formula ..