- anonymous

x=-b+/- multipled by the square root of b squared - 4 ac

- schrodinger

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- anonymous

yes?

- myininaya

\[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]

- anonymous

ok look my teacher gave us some equations and one of them are \[{x}^2+6x+9=0\]
and the answeres are x=-3 so i dont get it

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## More answers

- anonymous

yes, this is (x+3)^2 so x = -3

- anonymous

ok ;) so how do iget the answer for the first one

- anonymous

Take the coefficient of the terms:
i.e. the function is in ax^2+bx+c=0 form and plug the values of a, b, and c into the formula myiniaya posted, that is one way.

- anonymous

which one is the first one?

- anonymous

the first one is \[x=-b \pm \sqrt{b ^{2}- 4ac} \div 2a\] ;D

- myininaya

what do you want to solve for?

- anonymous

what about it?

- myininaya

we can solve it for b, a, or c?
its already solved for x

- anonymous

that is the quadratic formula to find roots.

- anonymous

well yeah the teacher wants us to find all thee a b and c but i dont reallly know how!

- myininaya

she wants you to solve the quadratic formula for a
then b
then c
are you sure?

- anonymous

yes thats what she said :S

- myininaya

k let's see if we can do it
let's try to solve for a first

- anonymous

ok ;D

- anonymous

it is impossible to solve this equation for a b and c

- myininaya

one sec

- myininaya

i think you can use the quadratic formula to solve for a lol

- anonymous

which is??

- myininaya

##### 1 Attachment

- anonymous

yes, but it impossible to solve for all three values of a,b and c

- myininaya

lol. i honestly don't think this what your teacher wants

- myininaya

i can solve for b and c
use the quad on b
and c is easiest

- anonymous

no, you cannot. x can hold only two values. you need atleast 3 equations to solve for 3 unknown variables.

- myininaya

a doeesnt have to be both
it can be one or the other
just like x

- anonymous

you may be able to get a,b and c in terms of the other variables, but that doesn't get you any closer to solving for them.

- myininaya

right but it sounded like he wanted us to solve the quadratic formula for each lol

- anonymous

oh, that is just an exercise in stupidity.

- anonymous

there is no point of that. I don't think their teacher asked them to solve for a,b and c.

- myininaya

me neither

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