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anonymous

  • 5 years ago

x=-b+/- multipled by the square root of b squared - 4 ac

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  1. anonymous
    • 5 years ago
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    yes?

  2. myininaya
    • 5 years ago
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    \[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]

  3. anonymous
    • 5 years ago
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    ok look my teacher gave us some equations and one of them are \[{x}^2+6x+9=0\] and the answeres are x=-3 so i dont get it

  4. anonymous
    • 5 years ago
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    yes, this is (x+3)^2 so x = -3

  5. anonymous
    • 5 years ago
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    ok ;) so how do iget the answer for the first one

  6. anonymous
    • 5 years ago
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    Take the coefficient of the terms: i.e. the function is in ax^2+bx+c=0 form and plug the values of a, b, and c into the formula myiniaya posted, that is one way.

  7. anonymous
    • 5 years ago
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    which one is the first one?

  8. anonymous
    • 5 years ago
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    the first one is \[x=-b \pm \sqrt{b ^{2}- 4ac} \div 2a\] ;D

  9. myininaya
    • 5 years ago
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    what do you want to solve for?

  10. anonymous
    • 5 years ago
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    what about it?

  11. myininaya
    • 5 years ago
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    we can solve it for b, a, or c? its already solved for x

  12. anonymous
    • 5 years ago
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    that is the quadratic formula to find roots.

  13. anonymous
    • 5 years ago
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    well yeah the teacher wants us to find all thee a b and c but i dont reallly know how!

  14. myininaya
    • 5 years ago
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    she wants you to solve the quadratic formula for a then b then c are you sure?

  15. anonymous
    • 5 years ago
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    yes thats what she said :S

  16. myininaya
    • 5 years ago
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    k let's see if we can do it let's try to solve for a first

  17. anonymous
    • 5 years ago
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    ok ;D

  18. anonymous
    • 5 years ago
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    it is impossible to solve this equation for a b and c

  19. myininaya
    • 5 years ago
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    one sec

  20. myininaya
    • 5 years ago
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    i think you can use the quadratic formula to solve for a lol

  21. anonymous
    • 5 years ago
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    which is??

  22. myininaya
    • 5 years ago
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  23. anonymous
    • 5 years ago
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    yes, but it impossible to solve for all three values of a,b and c

  24. myininaya
    • 5 years ago
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    lol. i honestly don't think this what your teacher wants

  25. myininaya
    • 5 years ago
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    i can solve for b and c use the quad on b and c is easiest

  26. anonymous
    • 5 years ago
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    no, you cannot. x can hold only two values. you need atleast 3 equations to solve for 3 unknown variables.

  27. myininaya
    • 5 years ago
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    a doeesnt have to be both it can be one or the other just like x

  28. anonymous
    • 5 years ago
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    you may be able to get a,b and c in terms of the other variables, but that doesn't get you any closer to solving for them.

  29. myininaya
    • 5 years ago
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    right but it sounded like he wanted us to solve the quadratic formula for each lol

  30. anonymous
    • 5 years ago
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    oh, that is just an exercise in stupidity.

  31. anonymous
    • 5 years ago
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    there is no point of that. I don't think their teacher asked them to solve for a,b and c.

  32. myininaya
    • 5 years ago
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    me neither

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