hi who can help me

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with?
Find the first terms of the product in ascending powers. (1-2x^2-x^4)(4+x^2-2x^4)
i know u helped me before but i am stuck

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Other answers:

please somone help me
oh ive already done this for you in detail. i dont understand why you keep reposting this.
no this is a diffeent one and i am stuck
(a+b)(c+d) = ac+ad+bc+bd. similarly expand your problem and post what you get
1-4+x^2+x^4
is it right
can u help me
please
hold on. stop spamming. let me read what you posted,
LOL I THOUGHT THE SAMMEEE THING
what
no that is wrong, toxic
ok can u help me further Ill repay you
repay me with what?
nm
can u help me please?
or can u tell me a wesite that provides free online tutoring
yes. use khan academy
do you understand algebra?
yes
but not really
okay. then you understand that (a+b)(c-d) = ac -ad +bc - bd ?
yes
well
well hello
then do you understand that \[(1-2x ^{2}-x ^{4})(4+x ^{2}-2x ^{4})\] is equal to \[(1 \times 4 +1 \times x ^{2}-1 \times 2x ^{2}) -(2x ^{2} \times4+2x ^{2}\times x ^{2}-2x ^{2}\times 2x ^{4})\] \[-(x ^{4}\times 4 +x ^{4} \times x ^{2}-x ^{4}\times 2x ^{4})\] ?
yes
ok
can you add all the x terms and x^2 terms and so on and post it here?
i am sorry, the first term in the equation i posted has -1 times 2x^2 in the end, it is supposed to be -1 times 2x^4
-5+x^2-7x^2
i guess is it right
no its not
where did you get -5 from?
oops sorry 4
help me
please
yes 4 is the first one.
-7x^2 is also correct
your answer is wrong. -5+x^2-7x^2 cannot be the answer. where did you get x^2-7x^2 from? isn't that just -6x^2?
so what is the answer
is it 4-7x^2-6x^2
is it right can u hel p
why do you have a -6x^2 there? -7x^2 - 6x^2 = -13x^2
that is not the answer.
can you just use the expansion I gave you and write out fully what you would get?
instead of guessing the answer like this?
ok i got 4-7x^2-6x^23
is it right if not can u help me
what do you mean by 6 x^23?
sorry 6x^2
I am not gonna help you until you write down and expand the expression I gave you.
that is the only way you will get the answer. you are just guessing the answer here.
didnt i do that
no you did not.
i dont know what u mean
can u explain
is it that hard to multiply 4 times 1?
4
right. so scroll up. and do all the multiplications I showed you in my expression and post your answer. then we will figure out the answer together.
(1×4+1×x^2−1×2x^4) = (4 +x^2 -2x^4) similarly write down the other two separately and post them here
i am sorry for being diffuct but i dont get what u said
then you shouldn't take math. Sorry I cannot help you any more.
take my advice and drop math. its not your strong suit
ok i got it
canu just write down the second equation for me i see it but can u do that for me so i can copy and paste
no.
ok i got -4x^2+2x^4+8x^2
is it right
and can u not be rue
rude
is it right
no it is not. do you know what a^2 times a^2 =?
a^4
(2x^2×4+2x^2×x^2−2x^2×2x^4) = ?
(2x^2×4+2x^2×x^2−2x^2×2x^4) = ( (2x^2×4) + (2x^2×x^2) − (2x^2×2x^4) )
now multiply the individual products within each brackets and write down the answer
8x^2+2x^4-4x^6
is it right
yes thats right. now do the last one too and post your answer
-4x^6
right
no i meant the third expression in the big expression I gave you
(x^4×4+x^4×x^2−x^4×2x^4) = ?
ok i got -2x^8+x^6+4x^4
is it right
yes. that is right.
so now do (4 +x^2 -2x^4) - (8x^2+2x^4-4x^6) - (-2x^8+x^6+4x^4) and post your answer
ok i got -8x^4-7x^2+4+3x^6-2x^8
is it right
yes thats right. now just write this expression in ascending powers.
ok 4-7x^2-8x^4
is it right
those are the first three terms in ascending powers of x
so yes, that is your answer. bye

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