hi who can help me

- toxicsugar22

hi who can help me

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- anonymous

with?

- toxicsugar22

Find the first terms of the product in ascending powers.
(1-2x^2-x^4)(4+x^2-2x^4)

- toxicsugar22

i know u helped me before but i am stuck

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## More answers

- toxicsugar22

please somone help me

- anonymous

oh ive already done this for you in detail. i dont understand why you keep reposting this.

- toxicsugar22

no this is a diffeent one and i am stuck

- anonymous

(a+b)(c+d) = ac+ad+bc+bd.
similarly expand your problem and post what you get

- toxicsugar22

1-4+x^2+x^4

- toxicsugar22

is it right

- toxicsugar22

can u help me

- toxicsugar22

please

- anonymous

hold on. stop spamming. let me read what you posted,

- anonymous

LOL I THOUGHT THE SAMMEEE THING

- toxicsugar22

what

- anonymous

no that is wrong, toxic

- toxicsugar22

ok
can u help me further
Ill repay you

- anonymous

repay me with what?

- toxicsugar22

nm

- toxicsugar22

can u help me please?

- toxicsugar22

or can u tell me a wesite that provides free online tutoring

- anonymous

yes. use khan academy

- anonymous

do you understand algebra?

- toxicsugar22

yes

- toxicsugar22

but not really

- anonymous

okay. then you understand that (a+b)(c-d) = ac -ad +bc - bd
?

- toxicsugar22

yes

- toxicsugar22

well

- toxicsugar22

well hello

- anonymous

then do you understand that
\[(1-2x ^{2}-x ^{4})(4+x ^{2}-2x ^{4})\]
is equal to
\[(1 \times 4 +1 \times x ^{2}-1 \times 2x ^{2}) -(2x ^{2} \times4+2x ^{2}\times x ^{2}-2x ^{2}\times 2x ^{4})\]
\[-(x ^{4}\times 4 +x ^{4} \times x ^{2}-x ^{4}\times 2x ^{4})\]
?

- toxicsugar22

yes

- toxicsugar22

ok

- anonymous

can you add all the x terms and x^2 terms and so on and post it here?

- anonymous

i am sorry, the first term in the equation i posted has -1 times 2x^2 in the end, it is supposed to be -1 times 2x^4

- toxicsugar22

-5+x^2-7x^2

- toxicsugar22

i guess is it right

- anonymous

no its not

- anonymous

where did you get -5 from?

- toxicsugar22

oops sorry 4

- toxicsugar22

help me

- toxicsugar22

please

- anonymous

yes 4 is the first one.

- anonymous

-7x^2 is also correct

- anonymous

your answer is wrong. -5+x^2-7x^2 cannot be the answer. where did you get x^2-7x^2 from? isn't that just -6x^2?

- toxicsugar22

so what is the answer

- toxicsugar22

is it 4-7x^2-6x^2

- toxicsugar22

is it right can u hel p

- anonymous

why do you have a -6x^2 there? -7x^2 - 6x^2 = -13x^2

- anonymous

that is not the answer.

- anonymous

can you just use the expansion I gave you and write out fully what you would get?

- anonymous

instead of guessing the answer like this?

- toxicsugar22

ok i got 4-7x^2-6x^23

- toxicsugar22

is it right
if not can u help me

- anonymous

what do you mean by 6 x^23?

- toxicsugar22

sorry 6x^2

- anonymous

I am not gonna help you until you write down and expand the expression I gave you.

- anonymous

that is the only way you will get the answer. you are just guessing the answer here.

- toxicsugar22

didnt i do that

- anonymous

no you did not.

- toxicsugar22

i dont know what u mean

- toxicsugar22

can u explain

- anonymous

is it that hard to multiply 4 times 1?

- toxicsugar22

4

- anonymous

right. so scroll up. and do all the multiplications I showed you in my expression and post your answer. then we will figure out the answer together.

- anonymous

(1×4+1×x^2−1×2x^4) = (4 +x^2 -2x^4)
similarly write down the other two separately and post them here

- toxicsugar22

i am sorry for being diffuct but i dont get what u said

- anonymous

then you shouldn't take math. Sorry I cannot help you any more.

- anonymous

take my advice and drop math. its not your strong suit

- toxicsugar22

ok i got it

- toxicsugar22

canu just write down the second equation for me i see it but can u do that for me so i can copy and paste

- anonymous

no.

- toxicsugar22

ok i got -4x^2+2x^4+8x^2

- toxicsugar22

is it right

- toxicsugar22

and can u not be rue

- toxicsugar22

rude

- toxicsugar22

is it right

- anonymous

no it is not.
do you know what a^2 times a^2 =?

- toxicsugar22

a^4

- anonymous

(2x^2×4+2x^2×x^2−2x^2×2x^4) = ?

- anonymous

(2x^2×4+2x^2×x^2−2x^2×2x^4) = ( (2x^2×4) + (2x^2×x^2) − (2x^2×2x^4) )

- anonymous

now multiply the individual products within each brackets and write down the answer

- toxicsugar22

8x^2+2x^4-4x^6

- toxicsugar22

is it right

- anonymous

yes thats right. now do the last one too and post your answer

- toxicsugar22

-4x^6

- toxicsugar22

right

- anonymous

no i meant the third expression in the big expression I gave you

- anonymous

(x^4×4+x^4×x^2−x^4×2x^4) = ?

- toxicsugar22

ok i got -2x^8+x^6+4x^4

- toxicsugar22

is it right

- anonymous

yes. that is right.

- anonymous

so now do (4 +x^2 -2x^4) - (8x^2+2x^4-4x^6) - (-2x^8+x^6+4x^4) and post your answer

- toxicsugar22

ok i got -8x^4-7x^2+4+3x^6-2x^8

- toxicsugar22

is it right

- anonymous

yes thats right. now just write this expression in ascending powers.

- toxicsugar22

ok 4-7x^2-8x^4

- toxicsugar22

is it right

- anonymous

those are the first three terms in ascending powers of x

- anonymous

so yes, that is your answer. bye

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