## anonymous 5 years ago 3y^2+5y=2

1. gw2011

3y^2+5y-2=0 (3y-1)(y+2)

2. anonymous

im confused how did you get -2 in the equation?

3. gw2011

You subtract 2 from each side of the equation which then gives you a -2 on the left hand side of the equation and zero on the right hand side of the equation. Once you do this, you can then factor the equation.

4. anonymous

ooohh! okay thanks!

5. anonymous

would the answer be y=1/3 and -2?

6. gw2011

You're welcome. Hopefully, you understood what I did. Yes, y=1/3 and -2.

7. anonymous

so for 4m^2 -100=0 would we do the same thing?

8. gw2011

Basically, you would do the same thing. The factor in this problem would be: (2m-10)(2m+10) and m=5 and -5.

9. anonymous

5x^2=40 this one were having alot of trouble on

10. amistre64

5x^2 - 40 = 0 5(x^2-8) x=+- 2sqrt(2) ??

11. gw2011

What you can do is to divide both sides by 5 and you get: x^2=8 x=square root of 8=+/- square root (4)(2)=+/-2(square root 2)

12. anonymous

$\sqrt{8} =+/-(4) (2)=+/-2\sqrt{2}$

13. anonymous

is that how you write it?

14. anonymous

im so confused

15. anonymous

im so confused

16. gw2011

To be completely correct you should put a +/- in front of square root 8 and use the same symbol for the square roots of 4 and 2. Otherwise, you are correct. What is the confusion?