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anonymous

  • 5 years ago

3y^2+5y=2

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  1. gw2011
    • 5 years ago
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    3y^2+5y-2=0 (3y-1)(y+2)

  2. anonymous
    • 5 years ago
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    im confused how did you get -2 in the equation?

  3. gw2011
    • 5 years ago
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    You subtract 2 from each side of the equation which then gives you a -2 on the left hand side of the equation and zero on the right hand side of the equation. Once you do this, you can then factor the equation.

  4. anonymous
    • 5 years ago
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    ooohh! okay thanks!

  5. anonymous
    • 5 years ago
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    would the answer be y=1/3 and -2?

  6. gw2011
    • 5 years ago
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    You're welcome. Hopefully, you understood what I did. Yes, y=1/3 and -2.

  7. anonymous
    • 5 years ago
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    so for 4m^2 -100=0 would we do the same thing?

  8. gw2011
    • 5 years ago
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    Basically, you would do the same thing. The factor in this problem would be: (2m-10)(2m+10) and m=5 and -5.

  9. anonymous
    • 5 years ago
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    5x^2=40 this one were having alot of trouble on

  10. amistre64
    • 5 years ago
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    5x^2 - 40 = 0 5(x^2-8) x=+- 2sqrt(2) ??

  11. gw2011
    • 5 years ago
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    What you can do is to divide both sides by 5 and you get: x^2=8 x=square root of 8=+/- square root (4)(2)=+/-2(square root 2)

  12. anonymous
    • 5 years ago
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    \[\sqrt{8} =+/-(4) (2)=+/-2\sqrt{2}\]

  13. anonymous
    • 5 years ago
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    is that how you write it?

  14. anonymous
    • 5 years ago
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    im so confused

  15. anonymous
    • 5 years ago
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    im so confused

  16. gw2011
    • 5 years ago
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    To be completely correct you should put a +/- in front of square root 8 and use the same symbol for the square roots of 4 and 2. Otherwise, you are correct. What is the confusion?

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