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anonymous
 5 years ago
3y^2+5y=2
anonymous
 5 years ago
3y^2+5y=2

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im confused how did you get 2 in the equation?

gw2011
 5 years ago
Best ResponseYou've already chosen the best response.0You subtract 2 from each side of the equation which then gives you a 2 on the left hand side of the equation and zero on the right hand side of the equation. Once you do this, you can then factor the equation.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0would the answer be y=1/3 and 2?

gw2011
 5 years ago
Best ResponseYou've already chosen the best response.0You're welcome. Hopefully, you understood what I did. Yes, y=1/3 and 2.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so for 4m^2 100=0 would we do the same thing?

gw2011
 5 years ago
Best ResponseYou've already chosen the best response.0Basically, you would do the same thing. The factor in this problem would be: (2m10)(2m+10) and m=5 and 5.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.05x^2=40 this one were having alot of trouble on

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.05x^2  40 = 0 5(x^28) x=+ 2sqrt(2) ??

gw2011
 5 years ago
Best ResponseYou've already chosen the best response.0What you can do is to divide both sides by 5 and you get: x^2=8 x=square root of 8=+/ square root (4)(2)=+/2(square root 2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{8} =+/(4) (2)=+/2\sqrt{2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is that how you write it?

gw2011
 5 years ago
Best ResponseYou've already chosen the best response.0To be completely correct you should put a +/ in front of square root 8 and use the same symbol for the square roots of 4 and 2. Otherwise, you are correct. What is the confusion?
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