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anonymous

  • 5 years ago

is it $61

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  1. myininaya
    • 5 years ago
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    i want $10000000000

  2. mattfeury
    • 5 years ago
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    Try and post yr replies on the earlier question, otherwise they won't make sense without much context :).

  3. anonymous
    • 5 years ago
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    ok thanks

  4. anonymous
    • 5 years ago
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    A student bought five books for the Fall semester. The costs of the books were $52, $70, $73, $63, and $47. Determine the student's average book cost? Determine the standard deviation of the students books? Determine the median price of the students books?

  5. anonymous
    • 5 years ago
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    is it $61? Is it $11.25? and is it $63?

  6. amistre64
    • 5 years ago
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    61

  7. anonymous
    • 5 years ago
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    does anyone know if this is the correct answers?

  8. amistre64
    • 5 years ago
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    305/5 = 61

  9. anonymous
    • 5 years ago
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    it may be 61. or not. How does one know?

  10. anonymous
    • 5 years ago
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    thank you amistre64

  11. anonymous
    • 5 years ago
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    do you know I find the standard deviation?

  12. amistre64
    • 5 years ago
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    ...i think i recall it; how many numbers?

  13. anonymous
    • 5 years ago
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    52, 70, 73, 63, 47 (5)

  14. amistre64
    • 5 years ago
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    whats the (5) doing there?

  15. anonymous
    • 5 years ago
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    total of five books, but you confirmed my answer, thank you.

  16. anonymous
    • 5 years ago
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    did you hear of statcrunch?

  17. amistre64
    • 5 years ago
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    47-63 = -16 52-63 = -9 63 mean= 0 70-63 = 7 73-63 = 10 squre the results

  18. anonymous
    • 5 years ago
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    std deviation is 9.2 i think

  19. amistre64
    • 5 years ago
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    256 81 49 100 ---- 486

  20. amistre64
    • 5 years ago
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    divide by 5-1? i think now

  21. anonymous
    • 5 years ago
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    I got the standard deviation at $11.25, is that incorrect?

  22. amistre64
    • 5 years ago
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    486 /4 ---- 121.5

  23. amistre64
    • 5 years ago
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    square root that?

  24. anonymous
    • 5 years ago
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    oh you may be right, I used the incorrect formula for std deviation

  25. amistre64
    • 5 years ago
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    11.02 or so....

  26. anonymous
    • 5 years ago
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    I got 11.247, so I rounded it to 11.24?

  27. anonymous
    • 5 years ago
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    I meant 11.25

  28. amistre64
    • 5 years ago
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    11.25 is close :)

  29. amistre64
    • 5 years ago
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    i think i did the steps right lol

  30. amistre64
    • 5 years ago
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    i know what i did wrong, i used the median and not the mean lol

  31. anonymous
    • 5 years ago
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    A researcher investigated last month's long distance telephone charges for residents of a small city. Ron lives in the city, and the Z-score of his last month's long distance telephone charges was -2.8. Describe Ron's charges as they relate to the average city resident?

  32. anonymous
    • 5 years ago
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    Do I use a normal distribution table to find Z?

  33. anonymous
    • 5 years ago
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    Ron’s charges represent only .3% of the residents who utilize long distance telephone services. (z-score: 0.0025)

  34. amistre64
    • 5 years ago
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    47-61 = 14 196 52-61 = 9 81 63-61 = 2 4 70-61 = 9 81 73-61 = 12 144 ---- 506/4 = 126.5 sqrt(126.5) = 11.247 got it finally lol

  35. anonymous
    • 5 years ago
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    thank you, your awesome!

  36. anonymous
    • 5 years ago
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    A researcher investigated last month's long distance telephone charges for residents of a small city. Ron lives in the city, and the Z-score of his last month's long distance telephone charges was -2.8. Describe Ron's charges as they relate to the average city resident? Ron’s charges represent only .3% of the residents who utilize long distance telephone services. (z-score: 0.0025)

  37. amistre64
    • 5 years ago
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    i havent heard of a z score before...new terminology for me ..

  38. anonymous
    • 5 years ago
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    oh ok

  39. anonymous
    • 5 years ago
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    do you statistics?

  40. amistre64
    • 5 years ago
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    taking stats and calc1 over the summer

  41. anonymous
    • 5 years ago
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    :0 ohhhhhhhhhhhhh

  42. amistre64
    • 5 years ago
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    taught myself some of it so far, but stats has been a backburner subject for me :)

  43. anonymous
    • 5 years ago
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    I know it is difficult, but not impossible

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