is it $61

- anonymous

is it $61

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- schrodinger

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- myininaya

i want $10000000000

- mattfeury

Try and post yr replies on the earlier question, otherwise they won't make sense without much context :).

- anonymous

ok thanks

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## More answers

- anonymous

A student bought five books for the Fall semester. The costs of the books were $52, $70, $73, $63, and $47. Determine the student's average book cost? Determine the standard deviation of the students books? Determine the median price of the students books?

- anonymous

is it $61? Is it $11.25? and is it $63?

- amistre64

61

- anonymous

does anyone know if this is the correct answers?

- amistre64

305/5 = 61

- anonymous

it may be 61. or not. How does one know?

- anonymous

thank you amistre64

- anonymous

do you know I find the standard deviation?

- amistre64

...i think i recall it; how many numbers?

- anonymous

52, 70, 73, 63, 47 (5)

- amistre64

whats the (5) doing there?

- anonymous

total of five books, but you confirmed my answer, thank you.

- anonymous

did you hear of statcrunch?

- amistre64

47-63 = -16
52-63 = -9
63 mean= 0
70-63 = 7
73-63 = 10
squre the results

- anonymous

std deviation is 9.2 i think

- amistre64

256
81
49
100
----
486

- amistre64

divide by 5-1? i think now

- anonymous

I got the standard deviation at $11.25, is that incorrect?

- amistre64

486
/4
----
121.5

- amistre64

square root that?

- anonymous

oh you may be right, I used the incorrect formula for std deviation

- amistre64

11.02 or so....

- anonymous

I got 11.247, so I rounded it to 11.24?

- anonymous

I meant 11.25

- amistre64

11.25 is close :)

- amistre64

i think i did the steps right lol

- amistre64

i know what i did wrong, i used the median and not the mean lol

- anonymous

A researcher investigated last month's long distance telephone charges for residents of a small city. Ron lives in the city, and the Z-score of his last month's long distance telephone charges was -2.8. Describe Ron's charges as they relate to the average city resident?

- anonymous

Do I use a normal distribution table to find Z?

- anonymous

Ron’s charges represent only .3% of the residents who utilize long distance telephone services. (z-score: 0.0025)

- amistre64

47-61 = 14 196
52-61 = 9 81
63-61 = 2 4
70-61 = 9 81
73-61 = 12 144
----
506/4 = 126.5
sqrt(126.5) = 11.247 got it finally lol

- anonymous

thank you, your awesome!

- anonymous

A researcher investigated last month's long distance telephone charges for residents of a small city. Ron lives in the city, and the Z-score of his last month's long distance telephone charges was -2.8. Describe Ron's charges as they relate to the average city resident? Ron’s charges represent only .3% of the residents who utilize long distance telephone services. (z-score: 0.0025)

- amistre64

i havent heard of a z score before...new terminology for me ..

- anonymous

oh ok

- anonymous

do you statistics?

- amistre64

taking stats and calc1 over the summer

- anonymous

:0 ohhhhhhhhhhhhh

- amistre64

taught myself some of it so far, but stats has been a backburner subject for me :)

- anonymous

I know it is difficult, but not impossible

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