anonymous
  • anonymous
square root of 27 a^2b^3c^5
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
\[\sqrt{27a ^{2}b ^{3}c ^{5}}\]
dumbcow
  • dumbcow
3abc^2sqrt(3bc)
anonymous
  • anonymous
27 = 3 times 3 times 3 = 3^2 times 3 b^3 = b^2 times b c^5 = c^2 times c^2 times c

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anonymous
  • anonymous
I know the answer I need an explanation
anonymous
  • anonymous
so if you do sqrt (27) that is sqrt(3^3 times3) = 3sqrt3 similarly the others too follow the same pattern
anonymous
  • anonymous
i meant sqrt(3^2 times3)
anonymous
  • anonymous
ok im clear there what about the variables
anonymous
  • anonymous
same thing. sqrt (a^2) = a sqrt(b^3) = b sqrt(b) sqrt(c^5) = c^2 sqrt(c)
anonymous
  • anonymous
what is confusing me is the c^5 i see that c^2c^2 c = c^5
anonymous
  • anonymous
yes c^2*c^2 = (c^2)^2
anonymous
  • anonymous
so c^5 = (c^2)^2 times c
anonymous
  • anonymous
ohhhhhhhhhhhhh your the best thanks so much
anonymous
  • anonymous
you are welcome.
anonymous
  • anonymous
for example, 16 = 4^2 but 4 = 2^2 so 4^2 = (2^2)^2 so sqrt 16 = sqrt(4^2) = sqrt (2^2)^2 = 2^2 = 4.

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