amistre64
  • amistre64
what is the volume of the solid, spun around the y axis of f(x) = 2x^2 -x^3, from x=[0,2] ?
Mathematics
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SOLVED
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katieb
  • katieb
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amistre64
  • amistre64
in other words, bounded by f(x) and the positive x axis
anonymous
  • anonymous
The integration Of the function squared. Only difference is, you solve for x in terms of y.
amistre64
  • amistre64
thats a bit difficult; lots of radicals involved; there is an easier way tho :)

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anonymous
  • anonymous
Yeah, there are 2 schools of thought, sorta. One is rings vs cylinders. The other is discs/shells/washers.
anonymous
  • anonymous
I usually prefer the rings, but with a quadratic, yeah it is more annoying.
amistre64
  • amistre64
yep; shells is your best bet take an average cylinder of height f(x) and cut it straight up and flatten it out so that it is 2pi x wide
anonymous
  • anonymous
Yeah, that'd do it. Haha
amistre64
  • amistre64
total area of the flattened cylinder is 2pi x [f(x)] 2pi [S] x[f(x)] dx in the interval gives you the volume :)
amistre64
  • amistre64
trying to do it the other way; nightmare integral lol
anonymous
  • anonymous
That's the beauty of choices though haha. Why did you ask a question you know the answer to?
amistre64
  • amistre64
to see if anyone could answer it of course ;)
amistre64
  • amistre64
i cant keep all the medals :)
anonymous
  • anonymous
Very fair. I'm up to my eeballs in calculus. But Haha that's just cuz I haven't been here in a bit. ;)
anonymous
  • anonymous
I just started a few days ago orso.
amistre64
  • amistre64
im taking it over the summer; calc1 that is
anonymous
  • anonymous
Oh cool. I just took the test to get credit through Calc 2.
amistre64
  • amistre64
i was gonna to save time, but cant make it 50 miles to the official testing cite .....
amistre64
  • amistre64
so i take the classes and do my crosswords and pass
anonymous
  • anonymous
Haha I play solitaire.
anonymous
  • anonymous
There, I posted one for y

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