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anonymous
 5 years ago
Is it true that for a quadratic equation ax^2+bx+c, the roots of the equation will always equal b/a?
anonymous
 5 years ago
Is it true that for a quadratic equation ax^2+bx+c, the roots of the equation will always equal b/a?

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0b/a aint even an option...unless you get real lucky lol

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1it will always be x=frac{b pm sqrt{b^24ac}{2a} a does not equal zero

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0There is a sort of cheat way to factor it though. I'm told it's not technically mathematically sound, but I like it and it works. Multiply a and b

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lol....its the french version

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0that only works for integer roots

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Then no wonder it's not mathematically sound. Ahaha

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0well, for roots that dont incvolve radicals

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0And no, not really. You just gotta tweak it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so it will equal b/a, assuming I'm only working with integers?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0no.....b/a aint even on the board

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but i keep trying to find a counterexample and cant

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0b/2a is a possibility; but that aint always a root unless the graph just touches once

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0if its a complete square than b/2a ia the only root

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0b/2a is to find the vertex...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i just want to find a counterexample to b/a being the sum of the roots

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0b/2a is the axis of symmetry; but its also half way between roots :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0my bad, i forgot to mention sum

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0if its a complete square than b/2a ia the only root

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1so you want to find a counterexample: how about x^25x+6=0 b/a=5 but there are two solutions and neither of them are 5 the solutions are x=3 and x=2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.03+2=5, forgot to mention that the sum of the roots = b/a

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the quad formula says; stand in the middle at b/2a....now look left and right an equal distance of sqrt(...)/2a

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol, did you just do that?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1yes does it make sense?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yea, do you know how it can be useful though?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1you can use it to sort of check yourself instead of plugging your answers back into the equation to check you can just see they add up to be b/a thanks for pointing this out i never realized it before

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1the square roots cancel because one was postive and one was negative just like 5+(5)=0 so you completely understand? thats amazing well unless you are passed algebra by now

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I am. My sis just brought this to my attention and I never realized it before. XD

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1by way it works for all numbers
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