anonymous
  • anonymous
Determine the volume of the solid obtained by rotating the portion of the region bounded by and that lies in the first quadrant about the y-axis.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
amistre64
  • amistre64
your trying to tempt me arent ya :)
anonymous
  • anonymous
Nope. Not in the least. ;)
amistre64
  • amistre64
is this saying the volume of the first quadrant spun around the y axis?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Yup. Which is to say, bound by both axis with the limits being each intersection
amistre64
  • amistre64
i appear to be missing a function to determine proper bound lol; or have gone blind :)
anonymous
  • anonymous
Oh you're right they didn't post... My bad! It's y=(x^1/3) and y =x/4
amistre64
  • amistre64
x^3 = x/4 would be the bounds then right...
amistre64
  • amistre64
cbrt(x)=x/4 typoed it lol
amistre64
  • amistre64
im going with 0 to 4
amistre64
  • amistre64
gotta redo that lol
amistre64
  • amistre64
0 to 8 ...
anonymous
  • anonymous
Yeah try again lol
anonymous
  • anonymous
There you go
amistre64
  • amistre64
my stupidity got in the way
anonymous
  • anonymous
I forgive you. 64 is awfully close to one. ;)
amistre64
  • amistre64
spin around the y axis....
amistre64
  • amistre64
we can do this from 0 to 2 on the y right
anonymous
  • anonymous
Less bored?
myininaya
  • myininaya
lol nerds!
amistre64
  • amistre64
less.... :)
anonymous
  • anonymous
Yes, if you mean in terms of y.
amistre64
  • amistre64
one radius is x=4y the other is .....
amistre64
  • amistre64
y^3?
anonymous
  • anonymous
I wouldn't do it that way.
amistre64
  • amistre64
\[\pi \int\limits_{0}^{2} [4y]^2 - [y^3]^2 dy\]
anonymous
  • anonymous
Though yes. You can. The top one being?
amistre64
  • amistre64
why is it gonna break?
anonymous
  • anonymous
Haha no,but yeah that's right. Let's pretend y just put inthe calculator and got it right because you can push buttons well. :)
amistre64
  • amistre64
i get 128/3 - 128/7
amistre64
  • amistre64
512/21 = 24.381 ??
amistre64
  • amistre64
if I do shelss; i wonder if i get the same result :)
anonymous
  • anonymous
That was fun :) it's 512 pi/21you forgot pi lol
amistre64
  • amistre64
i think i dropped a pi lol
amistre64
  • amistre64
ack!!.... yeah, just realized it :)
amistre64
  • amistre64
76.59 closer?
amistre64
  • amistre64
yes!! shell and disk are the same yay!!
amistre64
  • amistre64
\[2\pi \int\limits_{0}^{8} x(x^{4/3}) -x(\frac{x}{4}) dx\] = 76.59

Looking for something else?

Not the answer you are looking for? Search for more explanations.