Find the exact area of the minor segment of a circle if radius is 10cm and the angle subtended is 5π/6

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Find the exact area of the minor segment of a circle if radius is 10cm and the angle subtended is 5π/6

Mathematics
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t r^2/2
(5pi/6) 10(5) = 250pi/6
125pi/3 ?

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following so far, its converting the Sin(5π/6) into an exact ratio that gets me
so about 125 cm^2
dont need to convert sin; it just theta/2 r^2
the total area of a circle is 2pi/2 r^2 right?
no this is a minor segment :/ need to use the A=(1/2)r^2(@-Sin@) (where @ = theta and in radians)
define minor segment....is that new terminology?
aint it just the pie shaped piece?
http://www.tutornext.com/system/files/u37/Area%20of%20Segment.JPG
ohhhh minus the triangle lol
the triangle is side side/2 sin(t)
Minor means small. :)
yes but i need to use the above formula to figure out and converting the Sin part to exact ratios confuses the hell out of me
the sin(5pi/6) = 1/2
really... how? :/
you take a 30 degree angle and look across it at the 1 and to the hyp of 2
basic trig angle
but doesn't 5pi/6 = 150 degrees? :Z
yes; which has a reference angle of 30 degrees
150 and 30 have the same sin
ah yes, I get you now! cheers for the help :)
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