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amistre64

  • 5 years ago

what is the equation of the tangent plane to f(x,y) = x^2-y^2 +9 at the point (4,5,0) ?

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  1. anonymous
    • 5 years ago
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    Razzleberry squared?

  2. amistre64
    • 5 years ago
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    close :)

  3. anonymous
    • 5 years ago
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    No? How about... 3 Penguins and a goose?

  4. amistre64
    • 5 years ago
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    it begins with a gradient :)

  5. anonymous
    • 5 years ago
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    A+.

  6. amistre64
    • 5 years ago
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    x^2-y^2-z+9=0 g=<2x,2y,-1> p=( 4, 5, 0) ----------- n= <8,10,-1>

  7. anonymous
    • 5 years ago
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    Oh so close!

  8. amistre64
    • 5 years ago
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    8(x-4)+10(y-5)-z=0 right?

  9. anonymous
    • 5 years ago
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    Hmm yes

  10. amistre64
    • 5 years ago
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    now you aint agreeing with me just cause im right are ya?

  11. anonymous
    • 5 years ago
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    Why else would would I?

  12. amistre64
    • 5 years ago
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    i like this purpley pic; its the moon by a streetlamp about dusk time

  13. amistre64
    • 5 years ago
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    just before the mosquitoes come out ;)

  14. amistre64
    • 5 years ago
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    what you know about double integrals?

  15. anonymous
    • 5 years ago
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    You have to take the partial derivative with respect to x and then with respect to y....so...fx=2x and fy=2y...solving this with the given points you can figure it out. So, fx(4)=8 and fy(5)=10...so...8(x-4)+10(y-5)-z=0......Ya!...I believe that's correct sir!

  16. anonymous
    • 5 years ago
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    ur playing again amistre..tut..tut

  17. amistre64
    • 5 years ago
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    ...hangs head in shame.....but mr owletan, can i have another bwol of swill please?

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