anonymous
  • anonymous
if you want to find the velocity function of a problem would you just take the 1st derivative of the original equation? for ex. s(t)=-16t^2-64t+512?
Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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amistre64
  • amistre64
velocity is the derivative of position; yes the change of distance with respect to time/parameter
anonymous
  • anonymous
yeah ds/dt = v
anonymous
  • anonymous
ok now my next question is when you are asked to find the acceleration of an object how would you do that? after finding the 1st derivative/velocity function?

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anonymous
  • anonymous
differejntiate it again
anonymous
  • anonymous
a=dv/dt so a = d2v/dv2
anonymous
  • anonymous
so i should take the derivative of the velocity function?
amistre64
  • amistre64
what is curvature :)
amistre64
  • amistre64
the change in direction with respect to distance :)
anonymous
  • anonymous
no its the beauty of jennifer aniston..lol
anonymous
  • anonymous
yeah a=dv/dt
amistre64
  • amistre64
does your s(t) there indicate position of speed?
anonymous
  • anonymous
position as a function of time
amistre64
  • amistre64
the derivative of that function will tell you the speed it is going at any given position in time then
anonymous
  • anonymous
yea the reason why im asking this is because my professor gave us a question like this a while back and he asked for the velocity function, and then the acceleration. i got the velocity function no problem but then messed up and got the acceleration wrong. so just to clarify (velocity function = 1st derivative of original function, acceleration function = derivative of the velocity function?) thanks for all the help i really appreciate it
anonymous
  • anonymous
yeah its right
amistre64
  • amistre64
the derivative of velocity as part of acceleration.... if you do vectors
amistre64
  • amistre64
a = d^2s/dt^2. + k(ds/dt)^2
anonymous
  • anonymous
ok thanks everyone, im sure i will have a few more questions as this study session progressively gets more intense!

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