At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
velocity is the derivative of position; yes the change of distance with respect to time/parameter
yeah ds/dt = v
ok now my next question is when you are asked to find the acceleration of an object how would you do that? after finding the 1st derivative/velocity function?
differejntiate it again
a=dv/dt so a = d2v/dv2
so i should take the derivative of the velocity function?
what is curvature :)
the change in direction with respect to distance :)
no its the beauty of jennifer aniston..lol
does your s(t) there indicate position of speed?
position as a function of time
the derivative of that function will tell you the speed it is going at any given position in time then
yea the reason why im asking this is because my professor gave us a question like this a while back and he asked for the velocity function, and then the acceleration. i got the velocity function no problem but then messed up and got the acceleration wrong. so just to clarify (velocity function = 1st derivative of original function, acceleration function = derivative of the velocity function?) thanks for all the help i really appreciate it
yeah its right
the derivative of velocity as part of acceleration.... if you do vectors
a = d^2s/dt^2.
ok thanks everyone, im sure i will have a few more questions as this study session progressively gets more intense!