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anonymous

  • 5 years ago

Summation Evaluate these summations. a) N(E)k=1 (k-k^3) b) N-1(E)k=1 (k^2/N^2) Note that (E) is the summation symbol. Not sure how to do these. Help would be appreciated

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  1. anonymous
    • 5 years ago
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    hey m not sure i understand..r the terms on the right the expression for the kth term??

  2. anonymous
    • 5 years ago
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    do we have to evaluate the sum of the series whose term is k-k^3????clarify and i cn help

  3. anonymous
    • 5 years ago
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    sorry it's all squashed together, didn't notice! there are two questions: a) N (E) k=1 (k-k^3) b) N-1 (E) k=1 (k^2/N^2) where N = natural numbers and (E) is the summation symbol The N and N-1 for the questions are on top of the summation symbol and the k =1 are below the symbol. The (k-k^3) and (k^2/N^2) are on the right sides of the summation symbol.

  4. anonymous
    • 5 years ago
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    u can use the equation tab to write it in mathematical format

  5. anonymous
    • 5 years ago
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    ugghh it keeps squashing together - but a) and b) are separate questions

  6. anonymous
    • 5 years ago
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    N(N+1)/2 + [N(N+1)/2]^2

  7. anonymous
    • 5 years ago
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    thats a)

  8. anonymous
    • 5 years ago
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    as for b) (N-1)(N)(2N-1)/6N ^2

  9. anonymous
    • 5 years ago
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    \[\sum_{k=1}^{N}(k-k^3)\]

  10. anonymous
    • 5 years ago
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    yes uzma that's the correct format for a)

  11. anonymous
    • 5 years ago
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    and b?????

  12. anonymous
    • 5 years ago
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    \[\sum_{k}^{N-1}(k^2/N^2)\]

  13. anonymous
    • 5 years ago
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    i gave d answers

  14. anonymous
    • 5 years ago
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    Yes that's the correct one for b) him1618, thanks for your help :) and uzma too :)

  15. anonymous
    • 5 years ago
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    no prob

  16. anonymous
    • 5 years ago
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    did u understand the solution?

  17. anonymous
    • 5 years ago
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    Yes, thank you :)

  18. anonymous
    • 5 years ago
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    welcome:)

  19. anonymous
    • 5 years ago
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    wht tym is it there at ur place?

  20. anonymous
    • 5 years ago
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    9:02pm

  21. anonymous
    • 5 years ago
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    where r u?

  22. anonymous
    • 5 years ago
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    new zealand

  23. anonymous
    • 5 years ago
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    k...

  24. anonymous
    • 5 years ago
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    N(E)K=1(K-K^3) (E)1/1-K^2=1/N N=1-K^2 K=1 N=0

  25. anonymous
    • 5 years ago
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    what sort of followup is this kihaga???

  26. anonymous
    • 5 years ago
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    Yes! that is Honorata kihaga

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