A voltage source e(t), which has a value of 2V at t=0, rises exponentially to a final value of 6V with a time constant of 3sec. Determine the expression for e(t). I have possible answers a) e(t)=(6-4e^(-t/3))u(t) b) e(t)=6e^(-t/3)u(t) c)e(t)=(2+4e^(-t/3))u(t) d)e(t)(6-2e^(-3t))u(t)

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A voltage source e(t), which has a value of 2V at t=0, rises exponentially to a final value of 6V with a time constant of 3sec. Determine the expression for e(t). I have possible answers a) e(t)=(6-4e^(-t/3))u(t) b) e(t)=6e^(-t/3)u(t) c)e(t)=(2+4e^(-t/3))u(t) d)e(t)(6-2e^(-3t))u(t)

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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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i thnk ans shud b 1.
frst option
yeah right

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hey where this alma disappeard?
hey where this alma disappeard?
I will try.Thank you.
yr welcm!!!!!!!
it is e (t) = 6-4exp (-t / 3)

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