anonymous
  • anonymous
A voltage source e(t), which has a value of 2V at t=0, rises exponentially to a final value of 6V with a time constant of 3sec. Determine the expression for e(t). I have possible answers a) e(t)=(6-4e^(-t/3))u(t) b) e(t)=6e^(-t/3)u(t) c)e(t)=(2+4e^(-t/3))u(t) d)e(t)(6-2e^(-3t))u(t)
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
i thnk ans shud b 1.
anonymous
  • anonymous
frst option
anonymous
  • anonymous
yeah right

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
hey where this alma disappeard?
anonymous
  • anonymous
hey where this alma disappeard?
anonymous
  • anonymous
I will try.Thank you.
anonymous
  • anonymous
yr welcm!!!!!!!
anonymous
  • anonymous
it is e (t) = 6-4exp (-t / 3)

Looking for something else?

Not the answer you are looking for? Search for more explanations.