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anonymous
 5 years ago
Perform the following operation and determine an expression for e(t);
e(t)=10sin(wt +30degrees)10cos(wt 45degrees)
options are;
1.e(t)=0
2.e(t)=2.61sin(wt52.5degrees)
3.e(t)=18.7sin(wt17.2degrees)
4.e(t)=4.8sin(wt+36)
anonymous
 5 years ago
Perform the following operation and determine an expression for e(t); e(t)=10sin(wt +30degrees)10cos(wt 45degrees) options are; 1.e(t)=0 2.e(t)=2.61sin(wt52.5degrees) 3.e(t)=18.7sin(wt17.2degrees) 4.e(t)=4.8sin(wt+36)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0note: the possible answers are in sin, so we should map our phasors to sin

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so we want to change the cos term at the end to a sin term ( and it should also have a positive amplitude )

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if we draw a graph of y=cos(x) , we can see , geometrically , that this is the same graph as y=sin(x) but shifted to the right 90 degrees ( and to cause this shift we would need to subtract 90 from the arguement of the cos function, to get a +sin function

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so v(t) = 10sin(wt +30 ) + 10 sin ( wt 4590 ) v(t) = 10sin(wt+30) +10sin(wt 135) now, converting to phasors ( where "r < x " means amplitude r at an angle of x )

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0= 10<30 + 10 < 135 = 10cos(30) + j 10sin(30) + 10cos(135) + j 10sin(135) = 1.589 + j 2.071

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.02.61< 52.5 convert back to time domain, remember our phasors mapped to sin functions so v(t) = 2.61 sin (wt 52.5 )
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