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anonymous
 5 years ago
how do prove divergence of this infinite alternating series;
sum_(n=0)^\infty [1/(1n^4)]
anonymous
 5 years ago
how do prove divergence of this infinite alternating series; sum_(n=0)^\infty [1/(1n^4)]

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sum_{n=0}^{\infty} (1/(52/n^4 )\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0For alternating series, the following series must satisfy the following conditions to be convergent , else it'll be divergent : 1) lim n > infinity = 0 2) Series must be decreasing If it happens that the following series doesn't satisfy one of the conditions, then it's considered divergent. Another try is the kthterm test of divergence, you can simply take the limit of the following series and check, if the limit is "NOT" equal to zero then the series diverges, if the limit is = 0, then it's convergent ^_^ give it a try now, I hope this made things clear for you :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hmm I've tried the ratio test, and kth term test of div. without conclusion.. I thought the Leibniz test only holds for convergence, not divergence?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0never heard of leibniz test, try the AST

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, leibniz test is the same AST.. The AST gives me that sequence is decreasing, but the it's convergening towards 1/5, thus I cannot use the AST, right? can AST be used for proving divergence of series?
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