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anonymous
 5 years ago
kay tears off labels of all 10 soup cans
her mother knows there are 2 tomato and 8 vegetable
she selects 4 at random. what is the probability
a. exactly one of the 4 cans is tomato
b. none of the 4 cans is tomato
c. at least one of the 4 is tomato?
anonymous
 5 years ago
kay tears off labels of all 10 soup cans her mother knows there are 2 tomato and 8 vegetable she selects 4 at random. what is the probability a. exactly one of the 4 cans is tomato b. none of the 4 cans is tomato c. at least one of the 4 is tomato?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i am very confused...and i know the answers to these problems...i just dont know how to do them?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0on top of the fraction,the numerator is the no of ways o selecting 1 tomato can out of a possible 2 , and the denominator is the total no. of selections ie 10C4, selecting any 4 out of 10 cans

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no not really........the answer to the first is .8 so that is why i am confused

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.010!  sounds plausible? 2!(102)!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0check my solution...shes sayin its 0.8 the answer

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.02 2 2 2  perchance? 10 9 8 7

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0combo and perms are still new to me :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0id have to draw up a tree or something and count them out lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah...i am not sure if it is a combo though? def probablility

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0m 95% sure my methods right nelly

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0there are 45 ways to select 4 cans right? or did i mess that up too

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.010C4....what is that in longhand tho?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.010 9 8 7 6 5 4 3 2  4 3 2 6 5 4 3 2 10 9 8 7  4 3 2 5 3 2 7 = 15(14) = 210 right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0so we have 210 ways to do this lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0how many ways can we have 2 tcans?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0or is it easier to say how many ways to pick no tcans? 8 can ways then...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0pick one out of 2 cans is 2C1

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0but that doesnt gives us a total ways for tcans does it?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0if there are 8 ways to choose 4 cans 8!  ?? 4!4!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.08765432  432.432 8765  432 725 = 14*5 = 70

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.070/210 = 7/21 = 1/3; 33.33% ??

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0so the chance that 1 is at least a tcan could be 66' 2/3% does that seem reasonable?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.033' 1/3% chance we got no tcans 66' 2/3% chance we got at least 1 tcan seems good to me

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0nope the anwser is .8 blah

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0.8 is 80% which answer is .8? a,b or c?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.010C4 is the total number of ways to choose 4 cans.... 8C4 is the total number of ways to choose no tcans.... casue we removed them from the equation.... % = part/total % = 8c4/10c4 for no tcans 100 no tcan% = at least 1 tcan.... is my reasoning

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0whats the answers to b and c :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0exactly one of the 4 cans is tomato lets see if we take away one tcan; just for the sake of argument; we can do this then

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.09!  = 3.3.2.7 = 9(14) = 126 ways to possible ways to 4!5! to choose at least 1 tcan

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i am still very confused how to do the first as i get 122/210 = .53333

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0126 ways for 1 possible tcan and we still have 70 ways for no tcans..; i wonder

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.012670 would give us the number of ways for 1 tcan right? 126 70  56 ways that at least 1 tcan is in it... i hope lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.056/210 .  105/28.0000 ......not gonna be .8 lol
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